Needed assistance with checking the exit code returned by a node script in shell

Question

I had a script written in node.js which returns the appropriate exit code, either 0 for success and 1 for error. I am running this script in a shell script and need to compare the exit code to perform a few more operations, by using an if else block. Any suggestions how I can do that. I know we can use $? to get the exit code in shell. Thanks in advance.

CAMason · Answer 1 · 2012-10-22T17:02:03.420

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~~See exec(), particularly the return_var argument.~~

Apologies, I thought I saw a PHP tag.

edited Oct 22 '12 at 17:02

answered Oct 22 '12 at 16:43

CAMason

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but doesnt this have to do with PHP? – user1386101 Oct 22 '12 at 16:58
Excuse me, I thought I saw this tagged as [php] – CAMason Oct 22 '12 at 17:01

score 0 · Answer 2 · edited May 23 '17 at 12:12

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Exit Shell Script Based on Process Exit Code

Thats the solution.

rc=$?

if [[ $rc != 0 ]] ; then exit 2 fi

edited May 23 '17 at 12:12

Community

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answered Oct 22 '12 at 17:57

user1386101

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Needed assistance with checking the exit code returned by a node script in shell

2 Answers2