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Hi all I'm trying to send a javascript object through websockets:

the faye-websockets documentation says:

send(message) accepts either a String or a Buffer and sends a text or binary message over the connection to the other peer.

server side I'm using node and faye.

var WebSocket = require('faye-websocket');
var http = require('http');

var server = http.createServer();
server.addListener('upgrade', function(request, socket, head) {
    var ws = new WebSocket(request, socket, head);
    ws.send({topic:'handshake', data:'sdf487rgiuh7'});
});
server.listen(8000);

client side:

<script>
    var ws = new WebSocket('ws://localhost:8000');
    ws.onmessage = function(e) {
        console.log(e.data); //prints [Object object] string and not the object
    };
</script>

what is my error? Thanks

RzR
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frx08
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5 Answers5

104

WebSockets support sending and receiving: strings, typed arrays (ArrayBuffer) and Blobs. Javascript objects must be serialized to one of the above types before sending.

To send an object as a string you can use the builtin JSON support:

ws.send(JSON.stringify(object));

To send an object as a typed array you can use a javascript BSON library such as this one:

ws.send(BSON.serialize(object));

When you receive a WebSocket message you will need to deserialize it.

To deserialize a JSON string from a WebSocket message:

ws.onmessage = function (e) {
    var object = JSON.parse(e.data);
    ...
};

If you are using binary messages over WebSocket, then first you should set the binaryType attribute in order to receive all binary messages as typed arrays:

ws.binaryType = "arraybuffer";

Then the deserialization will look like this:

ws.onmessage = function (e) {
    var object = BSON.deserialize(e.data);
    ...
};

Here is a blog post about using BSON in Javascript;

kanaka
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    Your link is dead :/ And there aren't any readme.md on the git repo of js-bson. Gonna search some doc. – Vadorequest Nov 14 '14 at 13:18
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    Is it possible that the `onmessage` callback doesn't return the entire json string, and therefore `JSON.parse` throws a parsing error? – Martin Konecny Feb 17 '15 at 23:21
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    @MartinKonecny WebSockets is message based and messages are delivered in full (no partial messages). However, note that if you have something like websockify in the middle and you're actually talking to a regular TCP server on the other end, the message divisions are arbitrary (depend on TCP packet size, kernel window sizes, buffer sizes, etc). In that case you need to do some kind of re-assembly yourself. – kanaka Feb 18 '15 at 02:58
  • Thanks, I thought websockets were just plain sockets initiated via http. Good to know to is message based. – Martin Konecny Feb 18 '15 at 03:42
3

Client:

const bson = new BSON();
ws.binaryType = 'arraybuffer';

ws.onmessage = function(event) {
  console.log(bson.deserialize(Buffer.from(event.data)));
}

Server:

 const data = bson.serialize({ ... });
 ws.send(data);
Alex Ivasyuv
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2

I'm basically working with Socket.IO, but it looks like you need to stringify your data in the server and parse it in the client like so:

in the server:

ws.send(JSON.stringify({topic:'handshake', data:'sdf487rgiuh7'}));

in the client:

console.log(JSON.parse(e.data));
udidu
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2

add a function called json to the websocket object that transform in json and send the object passed by parameter

ws.json = (obj) => ws.send(JSON.stringify(obj));

ws.json({ message: "hello" });
Fabiel León
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    While this code may answer the question, providing additional context regarding how and/or why it solves the problem would improve the answer's long-term value. You can find more information on how to write good answers in the help center: https://stackoverflow.com/help/how-to-answer . Good luck – nima Oct 25 '22 at 08:48
0

From the client side you can just send it via JSON.strigify and in the server side just do JSON.parse to get the data

  • Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – J4GD33P 51NGH Jun 12 '23 at 11:30