Pattern matching in scala, check if number greater than

Question

Possible Duplicate:
Using comparison operators in Scala’s pattern matching system

For below method I receive an error : "'=>' expected but integer literal found."

Is it not possible to check if x is greater than another number and or is there an alternative approach to return "greater than 2" if '> 2' is matched ?

 def describe(x: Any) = x match {
    case 5 => "five"
    case > 2 => "greater than 2"
  }

score 10 · Accepted Answer · answered Oct 23 '12 at 19:36

10

Try:

def describe(x: Any) = x match {
  case 5 => "five"
  case x: Int if (x > 2) => "greater than 2"
}

answered Oct 23 '12 at 19:36

Matthew Farwell

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By the way, that thing called pattern match *guard*. – om-nom-nom Oct 23 '12 at 19:47
Yeah, I added the duplicate, or I would have expanded the answer. I don't think this answer will last very much longer... :-) – Matthew Farwell Oct 23 '12 at 19:50

Pattern matching in scala, check if number greater than

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