Convert String (representing decimal number) to long

Question

I've googled around a bit but could not find examples to find a solution. Here is my problem:

String s = "100.000";
long l = Long.parseLong(s);

The 2nd line of code which tries to parse the string 's' into a long throws a NumberFormatException.

Is there a way around this? the problem is the string representing the decimal number is actually time in milliseconds so I cannot cast it to int because I lose precision.

what that dot stands for? is it separator between 0's or decimal mark? — user902383, Oct 26 '12 at 15:40

score 4 · Answer 1 · answered Oct 26 '12 at 15:28

4

You could use a BigDecimal to handle the double parsing (without the risk of precision loss that you might get with Double.parseDouble()):

BigDecimal bd = new BigDecimal(s);
long value = bd.longValue();

answered Oct 26 '12 at 15:28

assylias

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score 4 · Answer 2 · answered Oct 26 '12 at 15:47

4

as i don't know is your 100.000 equals 100 or 100 000 i think safest solution which i can recommend you will be:

NumberFormat nf = NumberFormat.getInstance();
Number number = nf.parse("100.000");
long l = number.longValue();

answered Oct 26 '12 at 15:47

user902383

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score 2 · Answer 3 · answered Oct 26 '12 at 15:30

2

'long' is an integer type, so the String parse is rejected due to the decimal point. Selecting a more appropriate type may help, such as a double.

answered Oct 26 '12 at 15:30

Kenogu Labz

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http://stackoverflow.com/questions/888088/how-do-i-convert-a-string-to-double-in-java-using-a-specific-locale – Uncle Iroh Oct 26 '12 at 15:46
Yeah, I realized a bit late that this may be European notation. I may just delete this answer, as it seems others have covered the gamut of good possible solutions. – Kenogu Labz Oct 26 '12 at 16:21

score 0 · Answer 4 · answered Oct 26 '12 at 15:29

0

Just remove all spaceholders for the thousands, the dot...

s.replaceAll(".","");

answered Oct 26 '12 at 15:29

Thomas

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this would result in wrong number, 100.00 would be 10000 – Smith Jun 22 '14 at 14:32

score 0 · Answer 5 · answered Oct 26 '12 at 17:54

0

You should use NumberFormat to parse the values

answered Oct 26 '12 at 17:54

psabbate

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score 0 · Answer 6 · answered Jul 12 '15 at 17:42

0

We can use regular expression to trim out the decimal part. Then use parseLong

Long.parseLong( data.replaceAll("\..*", ""));

answered Jul 12 '15 at 17:42

jean joseph

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score -2 · Answer 7 · answered Oct 26 '12 at 15:36

-2

If you don't want to loose presision then you should use multiplication

    BigDecimal bigDecimal = new BigDecimal("100.111");
    long l = (long) (bigDecimal.doubleValue() * 1000);<--Multiply by 1000 as it
                                                         is miliseconds
    System.out.println(l);

Output:

answered Oct 26 '12 at 15:36

Amit Deshpande

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This is an extremely bad idea. Doubles are not lossless! Following this advice will likely lead to data corruption. – Torque May 16 '14 at 20:35

Convert String (representing decimal number) to long

7 Answers7