Converting two lines from VB.NET to C#

Question

I can't seem to properly convert the following from VB.NET to C#--

iKeyChar = Asc(mid(g_Key, i, 1))
iStringChar = Asc(mid(strCryptThis,i,1))

Here's my converted C# code, which doesn't seem to output equivalent values--

iKeyChar = Convert.ToInt32(g_Key.Substring(i, 1));
iStringChar = Convert.ToInt32(strCryptThis.Substring(i, 1));

Any help is greatly appreciated!

System Down · Answer 1 · 2012-10-26T22:28:10.287

8

That's because Mid is one based while Substring is zero based. Try it this way:

iKeyChar = (int)Convert.ToChar(g_Key.Substring(i-1, 1));
iStringChar = (int)Convert.ToChar(strCryptThis.Substring(i-1, 1));

edited Oct 26 '12 at 22:28

answered Oct 26 '12 at 21:33

System Down

1

Also Asc [returns](http://msdn.microsoft.com/en-us/library/zew1e4wc(v=vs.71).aspx) an ANSI code but Convert.ToInt32 tries to convert the string to a number, e.g. "1" is 1, "2' is 2 etc. – MarkJ Oct 26 '12 at 21:37
That kind of depends on if and what they have their Option Base set to doesn't it? – Daniel Graham Oct 26 '12 at 21:39
1

@MarkJ - Yeah I've heard of that. Do you know of an exact analog to Asc in C# (other than importing Microsoft.VisualBasic)? – System Down Oct 26 '12 at 21:42
@DanielGraham - "Option Base"? I thought VB.NET didn't have that? – System Down Oct 26 '12 at 21:43
@MarkJ - Apparently casting it to `char` *then* casting it to `int` should do the trick. – System Down Oct 26 '12 at 22:28

score 1 · Answer 2 · edited May 23 '17 at 12:12

1

edited May 23 '17 at 12:12

Community

answered Oct 26 '12 at 21:37

David Osborne

score 0 · Answer 3 · answered Oct 26 '12 at 21:36

0

Try this:

        int iKeyChar = Convert.ToChar(g_key.Substring(i, 1));
        int iStringChar = Convert.ToChar(strCryptThis.Substring(i, 1));

answered Oct 26 '12 at 21:36

Daniel Graham

score 0 · Answer 4 · answered Oct 26 '12 at 21:41

0

Simply access the desired char by its index withing the string and cast it to int:

iKeyChar = (int)g_Key[i - 1];
iStringChar = (int)strCryptThis[i - 1];

Note that index of the string characters is zero based (as System Down said in his post).

answered Oct 26 '12 at 21:41

4 Answers4