How to timeout within a bash script?

Question

Possible Duplicate:
Timeout a command in bash without unnecessary delay

So this is what I am trying to do -

for test in `ls Tests`; do

for file in `ls FileFolder`; do

output=`python devcap $test $file`

echo $test $file $output >>result.txt

done

done

How do I timeout the $output if it takes longer than say 5 seconds and move to the next $file?

Can I redirect the stderr to result.txt as well?

http://stackoverflow.com/questions/687948/timeout-a-command-in-bash-without-unnecessary-delay — doublesharp, Oct 29 '12 at 03:12

Jeff Robert Dagala · Answer 1 · 2012-10-29T06:27:58.830

0

try this:

for test in `ls Tests`; do

for file in `ls FileFolder`; do

output=`python devcap $test $file`

sleep 5

echo $test $file $output >>result.txt

done

done

edited Oct 29 '12 at 06:27

answered Oct 29 '12 at 03:12

Jeff Robert Dagala

613
7
19

I tried it.Its not working. The code just hangs up the shell and doesn't move forward. – user1738845 Oct 29 '12 at 05:09
have you tried to add sleep 5 in your code? btw I updated my answer – Jeff Robert Dagala Oct 29 '12 at 06:28

How to timeout within a bash script?

1 Answers1