regular expression to match file path in java

Question

Possible Duplicate:
C# - Regex for file paths e.g. C:\test\test.exe

I was trying out to create a regular expression to match file path in java

Like C:/WINDOWS/Profiles/myComputer/Desktop/test.xml

Pls help me.

Thank you very much

Do you need a regular expression? Moreover, this is going to give you trouble - the characters allowed are system-dependent; notably, there's File.separator, and some systems allow :, others do not. — ignis, Oct 31 '12 at 14:05
@see [File.exists()](http://docs.oracle.com/javase/7/docs/api/java/io/File.html#exists()). — ignis, Oct 31 '12 at 14:15

score 1 · Answer 1 · answered Oct 31 '12 at 14:45

you could try this,

 (?:[\w]\:|\\)(\\[a-z_\-\s0-9\.]+)+\.(?i)(txt|xml|gif|pdf|doc|docx|xls|xlsx)$

Explanation:

^(?:[\w]\:|\\) -- Begin with x:\ or \\
[a-z_\-\s0-9\.] -- valid characters are a-z| 0-9|-|.|_ (you can add more)
(?i) -- regular expression case-insensitive
(txt|xml|gif|pdf|doc|docx|xls|xlsx) -- Valid extension (you can add more)

score 0 · Answer 2 · edited Oct 31 '12 at 14:03

0

you could use something like this

"([a-zA-Z]:)?(\\\\[a-zA-Z0-9_.-]+)+\\\\?"

edited Oct 31 '12 at 14:03

Zaki

6,997
6
37
53

answered Oct 31 '12 at 14:02

Bahram

1,464
2
22
38

score 0 · Answer 3 · answered Oct 31 '12 at 14:08

Matcher ma = Pattern.compile("([a-zA-Z]:(?:/[\\w\\s]+)*/[\\w\\s]+\\.\\w+)")
                .matcher("C:/WINDOWS/Profiles/myComputer/Desktop/test.xml");
while (ma.find()) {
    System.out.println(ma.group(1));
}

Here's an example working for your case. maybe you need to add some characters that aren't allowed but it's just adding chars in [\w\s.] <- that would accept dots too.

regular expression to match file path in java

3 Answers3