Select a random number a random number of times but never the same random number twice

Question

Possible Duplicate:
How do I generate a list of n unique random numbers in Ruby?

I want to do:

Random.rand(0..10).times do
  puts Random.rand(0..10)
end

with the exception that if a random number has already been displayed it cannot be displayed again. How do I do this most easily?

score 8 · Accepted Answer · answered Nov 01 '12 at 15:39

8

As a quick one-liner:

rands = (0..10).to_a.shuffle[0, Random.rand(0..10)]

answered Nov 01 '12 at 15:39

Chowlett

I don't say it often enough - I _really love_ the way Ruby lets you do this sort of thing! – Chowlett Nov 01 '12 at 15:41
I imagine that in Python it could be even easier :) – Sergio Tulentsev Nov 01 '12 at 15:42
1

also: `Array(0..10).shuffle.take(rand(10))` – Mladen Jablanović Nov 01 '12 at 17:00

score 4 · Answer 2 · answered Nov 01 '12 at 15:43

4

If you are using Ruby 1.9 another one-liner with Array#sample

rands = (0..10).to_a.sample(Random.rand(0..10))

answered Nov 01 '12 at 15:43

nemesv

2 Answers2