Python - Splitting up a string into a list of paired chars

Question

Possible Duplicate:
How do you split a list into evenly sized chunks in Python?
Split string by count of characters

I have a string (which is hex), something like:

717765717777716571a7202020

I need to get it into the format:

0x71,0x77,0x65,0x71,0x77,0x77...

I'm not sure what the best method would be though

A string can be accessed just like a normal list, so all of the answers on that question will answer this one too. — Brendan Long, Nov 02 '12 at 20:27

score 5 · Accepted Answer · answered Nov 02 '12 at 20:28

>>> s = '717765717777716571a7202020'
>>> ['0x' + s[i:i+2] for i in range(0, len(s), 2)]
['0x71', '0x77', '0x65', '0x71', '0x77', '0x77', '0x71', '0x65', '0x71', '0xa7', '0x20', '0x20', '0x20']

If you want a comma-separated string as the result, you can use the following:

>>> ','.join('0x' + s[i:i+2] for i in range(0, len(s), 2))
'0x71,0x77,0x65,0x71,0x77,0x77,0x71,0x65,0x71,0xa7,0x20,0x20,0x20'

martineau · Answer 2 · 2012-11-02T21:17:21.437

0

Another way.

s = '717765717777716571a7202020'

print ','.join('0x'+''.join(d) for d in zip( *[iter(s)]*2 ))

Output:

0x71,0x77,0x65,0x71,0x77,0x77,0x71,0x65,0x71,0xa7,0x20,0x20,0x20

edited Nov 02 '12 at 21:17

answered Nov 02 '12 at 21:07

martineau

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You need to use the same `iter(s)`. e.g. `si = iter(s); ... zip(si,si)` -- this will give you `0x77,0x11,0x77 ...` – mgilson Nov 02 '12 at 21:09
@mgilson: Right...fixed. – martineau Nov 02 '12 at 21:20

Python - Splitting up a string into a list of paired chars

2 Answers2