In python, What does it mean if I assign a variable to a method?

Question

Reading the CherryPy tutorial I run into this

class HelloWorld(object):
    def index(self):
        return "Hello World!"
    index.exposed = True

So was does it mean? is exposed a variable in the local scope of the method index? If so, can I the value of expose change? I think it has something to do with python's MetaObject protocol to expose a class definition as an object itself.

score 4 · Answer 1 · answered Nov 03 '12 at 21:37

Functions are first-class objects in Python. A function definition creates a function object and binds it to the function's name. Function objects can have attributes, and that's what you are seeing here. The life time of a function attribute is bound the the life time of the function object, while the life time of a local variable inside the function is bound to a single execution of the function. They are completely separate.

score 2 · Accepted Answer · answered Nov 03 '12 at 21:37

No it's not a local variable of function index, rather it's a attribute of that function . And yes you can modify it outside the function too.

Read the PEP 232 on function attributes.

example:

In [2]: def foo():pass
   ...: 

In [3]: foo.bar="text"

In [4]: foo.bar
Out[4]: 'text'

In python, What does it mean if I assign a variable to a method?

2 Answers2