For example, I have two lists of points:
List<Point2D> a;
List<Point2D> b;
What would be the best way to find such i
and j
, so that a.get(i).distance(b.get(j))
is minimal?
The obvious solution is brute-force - calculate distance from each point in a
to each point in b
, keep the pair with shortest distance. But this algorithm is O(n^2)
, which is not good. Is there some better approach?