using SAX parser, how do you parse an xml file with out some foreknowledge of the structure of the xml?

Question

is there a way to implement the sax parser without passing the names of the elements in the xml as it is done in getChild method or equalsIgnoreCase(tagname)? Or is there a way to find out what are the names of tags in an xml and then pass it to Sax methods.

Even if you could, how do you know what the tag represents? – Simon Nov 05 '12 at 11:47 — Simon, Nov 05 '12 at 11:47
You should know what elements you are parsing! – Vikram Gupta Nov 05 '12 at 12:37 — Vikram Gupta, Nov 05 '12 at 12:37

score 0 · Answer 1 · edited May 23 '17 at 12:27

0

Look at this link

https://stackoverflow.com/a/4828765/1631457

1) is android sax parser example(don't anger me)

scroll down a little bit and you will see

2) org.xml parser example(i think you want this usage).

edited May 23 '17 at 12:27

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answered Nov 05 '12 at 12:43

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using SAX parser, how do you parse an xml file with out some foreknowledge of the structure of the xml?

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