12

I can't get my head around this. I need to somehow access the object in the parent loop but I'm not sure how. Here is what I've come up with so far. I marked the problematic area in the code with XXX:

Template:

{% for item in ingrcat %}
    <h2>{{ item.name }}</h2>
    <ul>
        {% for ingr in XXX %}
        <li><a href="#" id="i{{ ingr.id }}">{{ ingr.name }}</a></li>
        {% endfor %}
    </ul>
{% endfor %}

XXX - should be a list of ingredients belonging to the ingredience category which is currently being looped through in the parent loop.

View:

def home(request):
    if request.user.is_authenticated():
        username = request.user.username
        email = request.user.email
        foods = Food.objects.filter(user=request.user).order_by('name')
        ingredients = Ingredience.objects.filter(user=request.user).order_by('name')
        ingrcat = IngredienceCategory.objects.filter(user=request.user)

        context = {}
        for i in ingredients:
            context[i.category.name.lower()] = context.get(i.category.name.lower(), []) + [i]

        newcontext = {'foods': foods, 'ingredients': ingredients, 'ingrcat': ingrcat, 'username': username, 'email': email,}
    else:
        context = {}
        newcontext = {}

    context = dict(context.items() + newcontext.items())

    return render_to_response('home.html', context, context_instance=RequestContext(request))

Models:

from django.db import models
from django.contrib.auth.models import User

class IngredienceCategory(models.Model):
    name = models.CharField(max_length=30)
    user = models.ForeignKey(User, null=True, blank=True)

    class Meta:
        verbose_name_plural = "Ingredience Categories"

    def __unicode__(self):
        return self.name


class Ingredience(models.Model):
    name = models.CharField(max_length=30)
    category = models.ForeignKey(IngredienceCategory, null=True, blank=True)
    user = models.ForeignKey(User, null=True, blank=True)

    class Meta:
         verbose_name_plural = "Ingredients"

    def __unicode__(self):
        return self.name


class Food(models.Model):
    name = models.CharField(max_length=30)
    ingredients = models.ManyToManyField(Ingredience)
    html_id = models.CharField(max_length=30, null=True, blank=True)
    user = models.ForeignKey(User, null=True, blank=True)

    class Meta:
        verbose_name_plural = "Foods"

    def __unicode__(self):
        return self.name
finspin
  • 4,021
  • 6
  • 38
  • 66

2 Answers2

17

You can use backwards relationships.

{% for item in ingrcat %}
<h2>{{ item.name }}</h2>
<ul>
    {% for ingr in item.ingredience_set.all %}
    <li><a href="#" id="i{{ ingr.id }}">{{ ingr.name }}</a></li>
    {% endfor %}
</ul>
{% endfor %}

See documentation:

https://docs.djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward

Fozzle
  • 573
  • 1
  • 6
  • 18
  • Thanks for the pointer, I didn't know you could go backwards like that! However, I'm getting template error `Could not parse the remainder: '()' from 'item.ingredience_set.all()'`. I tried some variations of `ingredience_set` but couldn't make it work. – finspin Nov 05 '12 at 13:15
  • 1
    Ah yes, I was mistaken. In templates you don't use (). `{% for ingr in item.ingredience_set.all %}` should do the trick. – Fozzle Nov 05 '12 at 13:28
1

Do get_queryset on obj.manytomanyfield

{% for item in ingrcat %}
<h2>{{ item.name }}</h2>
<ul>
    {% for ingr in item.ingredients.get_queryset %}
    <li><a href="#" id="i{{ ingr.id }}">{{ ingr.name }}</a></li>
    {% endfor %}
</ul>
{% endfor %}
7guyo
  • 3,047
  • 1
  • 30
  • 31