You should look at the serialization attributes.
[JsonObject(MemberSerialization.OptIn)]
public class Page
{
[JsonProperty]
public string Text { get; set; }
// not serialized because mode is opt-in
public Book Book { get; set; }
}
Original answer
The aforementioned way should be prefered in most of the cases, but there are some where it is not enough.
There are two ways of doing it.
You can implement a JsonConverter, and override the WriteJson method to write only the properties you want.
class BookConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(Book);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
if (value.GetType() == typeof(T2))
{
JObject obj = new JObject();
Book b = value as Book;
obj["titre"] = b.Name;
obj["pages"] = b.Pages;
// This line can also be
// obj.WriteTo(writer, this);
// if you also need change the way pages are serialized.
obj.WriteTo(writer, null);
}
else
{
throw new NotImplementedException();
}
}
}
You can call it like that :
string result = JsonConvert.SerializeObject(
book,
new JsonSerializerSettings
{
Converters = new JsonConverter[] { new BookConverter() }
});
You can also create a JsonBook class, and serialize it.
class JsonBook{
public JsonBook(Book b){/*...*/}
public List<Pages> l;
public string title;
// No reference to Library.
}