52

I have been through a lot of googling for this, I found a lot of examples none of which was working for me. This is a simple issue which I feel has a simple answer without defining new classes\modules etc...

My code is this :

Console.WriteLine ("Please enter an IP address or hostname");
string host = Console.ReadLine ();
***IP = resolved "host"*** 
Socket s = new Socket (AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);    
s.Connect (IP, 80);
s.close();

How do I actually resolve the IP variable?

Ondrej Janacek
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Ba7a7chy
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6 Answers6

98

You can simply use the DNS class to do so:

IPHostEntry hostEntry;

hostEntry= Dns.GetHostEntry(host);

//you might get more than one ip for a hostname since 
//DNS supports more than one record

if (hostEntry.AddressList.Length > 0)
{
      var ip = hostEntry.AddressList[0];
      Socket s = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
      s.Connect(ip, 80);
}
Kolja
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  • This gives me : "the best overloaded methoud match for system.net.sockets.socket.connect(system.net.ipaddress, int) has some invalid arguments Argument #1 cannot convert system.net.iphostentry to type system.net.ipaddress – Ba7a7chy Nov 06 '12 at 10:34
39
string howtogeek = "www.howtogeek.com";
IPAddress[] addresslist = Dns.GetHostAddresses(howtogeek);

foreach (IPAddress theaddress in addresslist)
{
   Console.WriteLine(theaddress.ToString());
 }

from howtogeek

indiPy
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    This is the better answer if you want to take a string that could be either hostname or an IP address and get back a list of IP addresses. If you use GetHostEntry() from the accepted answer instead of GetHostAddresses(), providing a string that is already an IP address will still result in a DNS lookup to fill in the other information for the entry. – Andrew Bennett May 19 '22 at 18:19
11

Please take the note that accepted answer can resolve to IPv6. I attempted to connect to service that does not accept IPv6 as input string.

Therefore try this snippet if you care to get IPv4:

using System.Linq;

string host = "google.com";

Dns.GetHostEntry(host).AddressList.First(addr => addr.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
PiotrK
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3

This is the method I use to resolve a hostname to IPv4 and / or IPv6.

    using System.Net:

    // A host can have multiple IP addresses!
    public static IPAddress[] GetIPsByName(string hostName, bool ip4Wanted, bool ip6Wanted)
    {
        // Check if the hostname is already an IPAddress
        IPAddress outIpAddress;
        if (IPAddress.TryParse(hostName, out outIpAddress) == true)
            return new IPAddress[] { outIpAddress };
        //<----------

        IPAddress[] addresslist = Dns.GetHostAddresses(hostName);

        if (addresslist == null || addresslist.Length == 0)
            return new IPAddress[0];
        //<----------

        if (ip4Wanted && ip6Wanted)
            return addresslist;
        //<----------

        if (ip4Wanted)
            return addresslist.Where(o => o.AddressFamily == AddressFamily.InterNetwork).ToArray();
        //<----------

        if (ip6Wanted)
            return addresslist.Where(o => o.AddressFamily == AddressFamily.InterNetworkV6).ToArray();
        //<----------

        return new IPAddress[0];
    }
marsh-wiggle
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2

If all you want is to resolve a string that could represent either a hostname OR an IP address, you probably want to use System.Net.Dns.GetHostAddresses() rather than System.Net.Dns.GetHostEntry().

GetHostAddresses() skips the DNS lookup if the string parses to an IP address already, while GetHostEntry() will do a reverse lookup for the hostname.


https://learn.microsoft.com/en-us/dotnet/api/system.net.dns.gethostaddresses

Andrew Bennett
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-3

The IpAddress has the appropriate method for parsing hostname to IpAddress.

IPAddress addr = IPAddress.Parse(hostName)
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    This does not resolve the IP address from the host name. This will only create an `IPAddress` instance when `hostName` is a string in valid IPv4 or IPv6 format, which does not satisfy the original question. – NanoTree Sep 30 '21 at 15:59