Show AlertDialog if some condition is met

Question

First of all please bear with me because I'm new in Android.

I would like to write an application that can pop up a dialog box if a condition is met

example :

public class TestMax {

       public void main(String[] args) {
          int i = 5;
          int j = 5;
          int sum = i + j;

                   if (sum == 10) {


                // alert dialog box will appear and show the message -  "Answer is 10"

               }


    }

Appreciate your help. Thank you.

score 1 · Accepted Answer · answered Nov 09 '12 at 06:56

Add this when your condition is met:

AlertDialog alertDialog = new AlertDialog.Builder(this).create();
alertDialog.setTitle("Title");
alertDialog.setMessage("Message");
alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
  public void onClick(DialogInterface dialog, int which) {
  // TODO Add your code for the button here.   }
});
// Set the Icon for the Dialog
alertDialog.setIcon(R.drawable.icon);
alertDialog.show();

Refer http://developer.android.com/reference/android/app/AlertDialog.html. http://developer.android.com/guide/topics/ui/dialogs.html.

Juned · Answer 2 · 2012-11-09T07:05:44.973

do this. if you want to show only a alert dialog.

public void main(String[] args) 
{
        int i = 5;
        int j = 5;
        int sum = i + j;

        if (sum == 10) {
            new AlertDialog.Builder(yourclass.this)
                    .setTitle("Your answer is")
                    .setMessage(i)
                    .setNeutralButton("ok", null)
                    .setIcon(android.R.drawable.stat_sys_warning).show();
        }
}

score 0 · Answer 3 · answered Nov 09 '12 at 06:59

Please try this code....

Class to Pop Up the Dialog

if (condition) {

                showAlertDialog(Activityname.this, "Internet Connection",
                        "You have internet connection", true);
            } else {

                showAlertDialog(Activityname.this, "No Internet Connection",
                        "You don't have internet connection.", false);
            }

methods declaration for showdailog

    public void showAlertDialog(Context context, String title, String message, Boolean status) {
    AlertDialog alertDialog = new AlertDialog.Builder(context).create();

    // Setting Dialog Title
    alertDialog.setTitle(title);

    // Setting Dialog Message
    alertDialog.setMessage(message);

    // Setting alert dialog icon
    alertDialog.setIcon((status) ? R.drawable.success : R.drawable.fail);

    // Setting OK Button
    alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int which) {
        }
    });

    // Showing Alert Message
    alertDialog.show();
}

}

@user1811408 If you are satisfied with my answer the click on check button shown on left hand side of my answer. — Varun Vishnoi, Nov 09 '12 at 07:01

score 0 · Answer 4 · answered Nov 09 '12 at 07:02

public void main(String[] args) {
          int i = 5;
          int j = 5;
          int sum = i + j;

                   if (sum == 10) {
                   showAlertDialog(Activityname.this, "Internet Connection",
                    "You have internet connection", true);

                // alert dialog box will appear and show the message -  "Answer is 10"

               }

       public void showAlertDialog(Context context, String title, String message,   Boolean status) {
        AlertDialog alertDialog = new AlertDialog.Builder(context).create();

     // Setting Dialog Title
      alertDialog.setTitle(title);

    // Setting Dialog Message
    alertDialog.setMessage(message);

    // Setting alert dialog icon
    alertDialog.setIcon((status) ? R.drawable.success : R.drawable.fail);

    // Setting OK Button
   alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
      public void onClick(DialogInterface dialog, int which) {
       }
     });

   // Showing Alert Message
    alertDialog.show();


     }

Show AlertDialog if some condition is met

4 Answers4

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