Django redirect to view

Question

I have a view that I then want to redirect to another view with a success message. The signature of the method that I want to redirect to is:

quizView(request, quizNumber, errorMessage=None, successMessage=None)

And my attempt at redirecting to that view is:

return redirect(quizView, quizNumber=quizNumber, errorMessage=None, successMessage="Success!")

I've tried almost every combination of named and un-named parameters, but it doesn't work. Also, I tried just returning the the second view with the first, but then the URL is still where it was in the old view instead of appearing as though it has redirected. Is there a way to make this work?

The url entry of the view I'm trying to redirect to looks like " (r'^quizzes/(?P\d*)$', 'quizzes.views.quizView'), " — user1056805, Nov 11 '12 at 14:40

score 41 · Accepted Answer · answered Nov 11 '12 at 15:19

41

You haven't given your URL a name, so you need to use the whole path to the view function. Plus, that URL doesn't take errorMessage or successMessage parameters, so putting them into the reverse call will fail. This is what you want:

return redirect('quizzes.views.quizView', quizNumber=quizNumber)

answered Nov 11 '12 at 15:19

Daniel Roseman

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Just to improve the answer a bit - 'quizzes.views.quizView' should be the URL name from urls.py – The Godfather Apr 25 '18 at 07:55
is there any way to do it without URL name? – tyasird Sep 01 '20 at 10:10

score 6 · Answer 2 · answered Nov 11 '12 at 05:36

6

Can you try example 2 given in https://docs.djangoproject.com/en/dev/topics/http/shortcuts/#redirect

Make sure that it does the 'reverse' on the given view.
Your view name should be wrapped in single quotes/

answered Nov 11 '12 at 05:36

Siva Arunachalam

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I tried with the single quotes, same result. What do you mean by "Make sure that it does the 'reverse' on the given view." I don't think I'm doing that. – user1056805 Nov 11 '12 at 05:43
Create a simple example app and upload it to github. We will try to check and help – Siva Arunachalam Nov 11 '12 at 05:44
This is the error I get when I do all keyword arguments "Reverse for 'quizView' with arguments '()' and keyword arguments '{'successMessage': 'Students Successfully Added!', 'errorMessage': None, 'quizNumber': u'2'}' not found". If I do unnamed arguments I get the same "Reverse for 'quizView'..." – user1056805 Nov 11 '12 at 14:37

Super Kai - Kazuya Ito · Answer 3 · 2022-08-04T14:55:36.020

You need to give the view name "quizView" to the path in "myapp/urls.py" as shown below:

# "myapp/urls.py"

from django.urls import path
from . import views

app_name = "myapp"

urlpatterns = [                       # This is view name
    path('quizView/', views.quizView, name="quizView")
]

Then, you need the conbination of the app name "myapp", colon ":" and the view name "quizView" as shown below. In addition, you don't need to import the view "quizView" in "myapp/views.py". And, you don't need to modify path() in "myapp/urls.py" if you pass data with session with request.session['key'] as shown below:

# "myapp/views.py"

from django.shortcuts import render, redirect

def my_view(request): # Here
    request.session['quizNumber'] = 3
    request.session['errorMessage'] = None
    request.session['successMessage'] = "Success!"

                    # Here
    return redirect("myapp:quizView")

def quizView(request):
    return render(request, 'myapp/index.html', {})

Then, this is Django Template:

# "myapp/index.html"

{{ request.session.quizNumber }}     {# 3 #}
{{ request.session.errorMessage }}   {# None #}
{{ request.session.successMessage }} {# Success! #}

score -2 · Answer 4 · answered Feb 05 '17 at 07:14

-2

You should Refer this https://docs.djangoproject.com/en/1.11/topics/http/shortcuts/#redirect

For redirect inside view. Its very easy either you redirect using creating a url for view or call inside the view also.

answered Feb 05 '17 at 07:14

Mayank Pratap Singh

183
8

Django redirect to view

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