parse xml feed using python feedparser

Question

i have this feed which i would like to pull the info out of http://www.boutique-artisans-du-monde.com/rss/catalog/category/cid/6/store_id/1/

from the code i have

try:
   xml = urllib2.urlopen(link_rss)
except urllib2.URLError, e:
   pass
else:
   f = feedparser.parse(xml)
   print len(f.entries)

when i print the len(f.entries) maximum entries i get is 50 what is the correct way to pull all the entries?

score 2 · Accepted Answer · edited May 23 '17 at 12:27

2

I think it returns all the entries, maybe that's only what the feed contains. If you want to pull older entries you will have to find the correct feed and pass it to the feedparser RSS is just an XML file stored at the server.

check this answer

edited May 23 '17 at 12:27

Community

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answered Nov 11 '12 at 17:40

iabdalkader

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Yep, the feed only contains 50 items – Kien Truong Nov 11 '12 at 17:43
@Dikei I guess this answers your question :) – iabdalkader Nov 11 '12 at 17:44
It's not my question though :) – Kien Truong Nov 11 '12 at 17:46
@Dikei sorry, confused you for the OP :) – iabdalkader Nov 11 '12 at 17:52

parse xml feed using python feedparser

1 Answers1