How can I parse JSON data from an API call?

Question

Here's what I have at the moment:

<?php
    $string = file_get_contents("http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key=##################################&steamids=76561198040884950");
    $json=json_decode($string);
?>

<script type="text/javascript">
        alert("<?php echo $json; ?>");
</script>

All I'm trying to do at this stage is receive the JSON information. I'm quite new to jQuery and PHP so not sure where I'm going wrong.

Yes, you are doing correct `json_decode`. but what you want exactly ? — GBD, Nov 12 '12 at 05:47
Publicly posting your Steam API key is a violation of the Steam API terms of use. You should edit your post to remove it ASAP. — Chris Hayes, Nov 12 '12 at 05:51

score 1 · Answer 1 · answered Nov 12 '12 at 05:49

1

check this out http://api.jquery.com/jQuery.parseJSON/ ,something like this

var obj = jQuery.parseJSON('{"name":"John"}');
alert( obj.name === "John" );

answered Nov 12 '12 at 05:49

rajesh kakawat

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score 1 · Accepted Answer · answered Nov 12 '12 at 05:50

By using json_decode you're converting the JSON from a string (which can be universally understood and parsed) to a PHP object or array, which will not print out the way you wish. You should avoid converting it and simply do something like this:

<?php
    $string = file_get_contents("http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key=...&steamids=76561198040884950");
?>

<script type="text/javascript">
        var json = <?php echo $string; ?>;
        // do things with the JSON; parse it into an object, etc
</script>

score 1 · Answer 3 · answered Nov 12 '12 at 05:52

1

When using json_decode through PHP, your output will be returned in an array;

When returning json information from external files to jquery scripts you must ensure to use the proper syntax. Codex

answered Nov 12 '12 at 05:52

Samuel Cook

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score 1 · Answer 4 · edited May 23 '17 at 12:31

1

Secondly I'm not sure if you know, but in using file_get_contents, you need your php.ini file to have the following flag:

allow_url_fopen = 1

If you don't want to, there are alternatives: Check it

edited May 23 '17 at 12:31

Community

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answered Nov 12 '12 at 05:56

Dane Balia

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score 1 · Answer 5 · answered Nov 12 '12 at 06:05

1

Try using <?php print_r($json); ?> instead of echo. It's doing what you want it to. echo just isn't any good at handling arrays.

answered Nov 12 '12 at 06:05

Joshua Kaiser

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How can I parse JSON data from an API call?

5 Answers5