Can't find the file path which created by myself in android source code

Question

I am testing something.

I created assets folder in packages/apps/Camera/ and added the test.txt file in the folder.

But when I accessed the file in the onCreate() method according the following code fragment, I found I can't get the file.

    File file = new File("/assets/test.txt");
    BufferedReader reader = null;
    try {
        Log.v("jerikc","read the file");
        reader = new BufferedReader(new FileReader(file));
        String tempString = null;
        int line = 1;

        while ((tempString = reader.readLine()) != null) {

            Log.v("jerikc","line " + line + ": " + tempString);
            line++;
        }
        reader.close();
    } catch (IOException e) {
        Log.v("jerikc","exception");
        e.printStackTrace();
    } finally {
        if (reader != null) {
            try {
                reader.close();
            } catch (IOException e1) {
            }
        }
    }

The log were :

V/jerikc (3454): read the file

V/jerikc (3454): exception

I think I add the wrong path.("/assets/test.txt") . So what's the right path?

Some other informations:

Where my real code is a Util Class, there isn't the context. If I add the context, the code structure will have a big change.

Thanks.

http://stackoverflow.com/questions/4789325/android-path-to-asset-txt-file. Maybe will help you — Yahor10, Nov 14 '12 at 11:19
I think you missed the **.** in your path _"/assets/test.txt"_, how about try this _"./assets/test.txt"_. Here the dot means your current working directory. — Jin Chen, Nov 14 '12 at 11:23
But I have no context in my test class. Because what's my test is a Util , there isn't context. So I can't use the getAssets() method. — Jerikc XIONG, Nov 14 '12 at 11:25

score 1 · Accepted Answer · answered Nov 14 '12 at 11:27

1

You have to read assets like below

AssetManager mAsset = context.getAssets();

InputStream is = mAsset.open("test.txt");

answered Nov 14 '12 at 11:27

nandeesh

24,740
6
69
79

Sorry , my question isn't clear. I can't use the context in my project ,it's just a Util class. Thanks very much. Is there any other solution? – Jerikc XIONG Nov 14 '12 at 11:29
I dont think you can access assets without context, you can always pass context as a parameter in function – nandeesh Nov 14 '12 at 11:35
But how to explain that it's ok when I create a android project independently， not in android source code project . – Jerikc XIONG Nov 14 '12 at 11:52
you mean you are creating a external library? – nandeesh Nov 14 '12 at 14:12
No. It's just a file , not a external library. – Jerikc XIONG Nov 15 '12 at 03:09

score 1 · Answer 2 · answered Nov 14 '12 at 11:37

1

you can get the path from assest folder by this way...try this...

File file = new File("file:///assets/test.txt");

instead of this..

File file = new File("/assets/test.txt");

answered Nov 14 '12 at 11:37

Mehul Ranpara

4,245
2
26
39

The same as **File file = new File("/assets/test.txt");** – Jerikc XIONG Nov 14 '12 at 11:46

Can't find the file path which created by myself in android source code

2 Answers2