This question still shows as one of the first search results. So I would like to share a my solution and hope it will help more people out. This will also work when you have a table with many levels of parent and child relations. Although it is quite a slow solution. The top level has NULL
as parent.
+---------+---------+
| id | parent |
+---------+---------+
| 1 | NULL |
| 2 | 1 |
| 3 | 1 |
| 4 | 2 |
+---------+---------+
In my approach I will use a procedure that will recursively call itself and keep prepending the path with the parent of the requested id
until it reaches the NULL
parent.
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `PATH`(IN `input` INT, OUT `output` VARCHAR(128))
BEGIN
DECLARE _id INT;
DECLARE _parent INT;
DECLARE _path VARCHAR(128);
SET `max_sp_recursion_depth` = 50;
SELECT `id`, `parent`
INTO _id, _parent
FROM `database`.`table`
WHERE `table`.`id` = `input`;
IF _parent IS NULL THEN
SET _path = _id;
ELSE
CALL `PATH`(_parent, _path);
SELECT CONCAT(_path, '-', _id) INTO _path;
END IF;
SELECT _path INTO `output`;
END $$
DELIMITER ;
To use the results in an ORDER BY
clause you will need a FUNCTION
too that wraps the results of the PROCEDURE
.
DELIMITER $$
CREATE DEFINER=`root`@`localhost` FUNCTION `GETPATH`(`input` INT) RETURNS VARCHAR(128)
BEGIN
CALL `PATH`(`input`, @path);
RETURN @path;
END $$
DELIMITER ;
Now we can use the recursive path to sort the order of the table. On a table with 10000 rows it takes just over a second on my workstation.
SELECT `id`, `parent`, GETPATH(`id`) `path` FROM `database`.`table` ORDER BY `GETPATH`(`id`);
Example output:
+---------+---------+---------------+
| id | parent | path |
+---------+---------+---------------+
| 1 | NULL | 1 |
| 10 | 1 | 1-10 |
| 300 | 10 | 1-10-300 |
| 301 | 300 | 1-10-300-301 |
| 302 | 300 | 1-10-300-302 |
+---------+---------+---------------+
5 rows in set (1,39 sec)