My script calculate the difference in 2 time. Like this:
lasted = datetime.strptime(previous_time, FMT) - datetime.strptime(current_time, FMT)
It returns me a timedelta object. Currently, it gives me difference in seconds.
How can I format it for display nicely?
e.g. convert "121" to "00:02:01"?
Thank you.
Have you tried using str()?
>>> a = datetime.now()
>>> b = datetime.now() - a
>>> b
datetime.timedelta(0, 6, 793600)
>>> str(b)
'0:00:06.793600'
Alternatively, you can use string formatting:
>>> a = datetime.now()
>>> b = datetime.now() - a
>>> s = b.total_seconds()
>>> '{:02}:{:02}:{:02}'.format(s // 3600, s % 3600 // 60, s % 60)
'00:00:06'
You can truncate the seconds when using str by creating a new timedelta object
>>> a = datetime.now()
>>> b = datetime.now()
>>> c = b-a
>>> str(c)
'0:00:10.327705'
>>> str(timedelta(seconds=c.seconds))
'0:00:10'
[insert shameless self-promotion disclamer here]
You can use https://github.com/frnhr/django_timedeltatemplatefilter
It's packaged as a tempalte filter for Django, so here is the important part, just plain Python:
def format_timedelta(value, time_format="{days} days, {hours2}:{minutes2}:{seconds2}"):
if hasattr(value, 'seconds'):
seconds = value.seconds + value.days * 24 * 3600
else:
seconds = int(value)
seconds_total = seconds
minutes = int(floor(seconds / 60))
minutes_total = minutes
seconds -= minutes * 60
hours = int(floor(minutes / 60))
hours_total = hours
minutes -= hours * 60
days = int(floor(hours / 24))
days_total = days
hours -= days * 24
years = int(floor(days / 365))
years_total = years
days -= years * 365
return time_format.format(**{
'seconds': seconds,
'seconds2': str(seconds).zfill(2),
'minutes': minutes,
'minutes2': str(minutes).zfill(2),
'hours': hours,
'hours2': str(hours).zfill(2),
'days': days,
'years': years,
'seconds_total': seconds_total,
'minutes_total': minutes_total,
'hours_total': hours_total,
'days_total': days_total,
'years_total': years_total,
})
Doesn't get more simple than that :) Still, check out the readme for a few examples.
For your example:
>>> format_timedelta(lasted, '{hours_total}:{minutes2}:{seconds2}')
0:02:01
That fractional second bit is sometimes unwanted from a timedelta. A quick truncate of that fractional bit with a split and discard:
a = datetime.now()
b = datetime.now() - a
then
str(b).split('.')[0]
(assuming applications where fraction of a second is irrelevant to you)
Hope this fix your problem,
import datetime
start = datetime.datetime(2012,11,16,11,02,59)
end = datetime.datetime(2012,11,20,16,22,53)
delta = end-start
print ':'.join(str(delta).split(':')[:3])
In [29]: import datetime
In [30]: start = datetime.datetime(2012,11,16,11,02,59)
In [31]: end = datetime.datetime(2012,11,20,16,22,53)
In [32]: delta = end-start
In [33]: print ':'.join(str(delta).split(':')[:3])
4 days, 5:19:54
Expanding on @blender's answer. In case you're interested in millisecond resolution
a = datetime.now()
b = datetime.now() - a
s = b.seconds
ms = int(b.microseconds / 1000)
'{:02}:{:02}:{:02}.{:03}'.format(s // 3600, s % 3600 // 60, s % 60, ms)
