How to fix file_get_contents() warning: Failed to open stream?

Question

I don't know why but I always got this error when I want to get PHP data with file_get_contents.

I have checked my PHP.ini and allow_url_fopen is: ON so that couldn't be the problem.

Here is the code I'm using:

$id='54352';
$url='http://www.google.com';
$data = file_get_contents('http://www.####.###/###.php?id='.$id.'&url='.urlencode($url));

var_dump($data);

I don't know what is going on here, I just get this error message and the value: bool(false).

I have also tried cURL, but it doesn't return ANY value to me.

Can anyone please help me?

well whatever url you requests is returning a 500 status code... whats there to wonder about? — Hannes, Nov 16 '12 at 16:41
But it SHOULD work, a lot of people using it, I don't think that url would be bad. — user1406071, Nov 16 '12 at 16:43
shoulda coulda woulda :) ether your request url is not well formed or whatever you call returns a 500 for whatever reason — Hannes, Nov 16 '12 at 16:54
have you tried to access the URL in a browser? what do you get then? — Markus Köhler, Jul 29 '15 at 14:48

score 2 · Answer 1 · edited Mar 16 '15 at 23:17

2

Try something like:

 $data = file_get_contents('http://www.####.###/###.php?id='.$id.'&url='.urlencode($url),true);

edited Mar 16 '15 at 23:17

kenorb

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answered Nov 16 '12 at 16:49

NullPoiиteя

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sorry I have miswritten it in this code, but its like var_dump($data) in my original code... – user1406071 Nov 16 '12 at 16:52

How to fix file_get_contents() warning: Failed to open stream?

1 Answers1