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I have been working on a table in a mysql database being hold locally on a wamp server I am using the phpmyadmin area with in wamp to run the querys. I am trying to get the data to do the following:

Can anyone help I have a table with a number of records for plants. A plant can have a number of names the table shows this as different records. The table is called new_plantsname

plantid name
1       tree
1       rose
2       bush
3       tree
3       bush
3       rose

this continues for over 3000 records

what i want is it to combined records with same plantid and show the different names in different columns:

plantid name1 name2 name3 ...
1       tree  rose  NULL
2       shrub NULL  NULL
3       tree  rose  bush

etc

From a glance I believe a plant has no more than 4 names.

Can one help me the query to do this. I also want to save results to a new table

Someone has given me the following for the answer: 

select plantid,
  max(case when nameRn = 'name1' then name end) Name1,
  max(case when nameRn = 'name2' then name end) Name2,
  max(case when nameRn = 'name3' then name end) Name3,
  max(case when nameRn = 'name4' then name end) Name4
from
(
  select plantid, name,
      concat('name', @num := if(@plantid = `plantid`, @num + 1, 1)) as nameRn,
      @plantid := `plantid` as dummy
  from
  (
    select plantid, name, @rn:=@rn+1 overall_row_num
    from yourtable, (SELECT @rn:=0) r
  ) x
  order by plantid, overall_row_num
) src
group by plantid;

This seem to work while no errors but it didnt combine the records it only kept the name of the first record with the id not the rest. DATA USED: 

plantid     name
    1       tree
    1       rose
    2       tree
    3       rose
    3       bush
    3       rose

RESULTS:

results show null added for all except first name

Can anyone help

zaratjlc
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  • Yes I no it works here but when I run it in the phpmyadmin of wamp it doesn't give that result it only give me the first name and puts null for the rest – zaratjlc Nov 16 '12 at 20:14
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    Id suggest then you havent got the same data structure you are saying here. As a result i think its up to you to work out the next stage. The example previously given clearly works in the demo above. Failing that, perhaps phpmyadmin isnt able to handle the query properly. Have you tried running the query in a different admin tool??? – Phill Healey Nov 16 '12 at 21:13

1 Answers1

24

The problem is that MySQL does not have a good way of enumerating rows. The use of the constant is not guaranteed to work, alas, according to the MySQL documentation. It often does work, but it can also be problematic.

I would suggest that you concatenate the names together into a single field. The result would look like:

1     tree,rose
2     tree
3     tree,bush,rose

Using the SQL:

select plantid, group_concat(name separator ',')
from t
group by plantid

If you really wanted the names in separate columns, two options come to mind. One is to use the results from above and then parse the result into separate strings. The other alternative is to use a self-join and aggregation to calculate a sequential number, like this:

select p.plantid, p.name, count(*) as seqnum
from t p left outer join
     t pprev
     on p.plantid = pprev.plantid and
        p.name >= pprev.name
group by p.plantid, p.name

And use this as the subquery.

Gordon Linoff
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