how to apply bgcolor in table using echo command

Question

I want to apply background colour to a table. I have written table using echo command , but am confused about how to apply bgcolor can any one guide me..

print("<table align='center' width='50%' border=1> ");
echo "<TR><TD> Sr.No </td>";
echo "<td  width=\"16%\" bgcolor=\"#CCCCCC\"> delete</td>";
echo "<Td> File Name </td> ";
echo "<td> Share It </td>";
echo "</tr></table>";

instead of bgcolor you should use CSS's background-color property. =o) — kittycat, Nov 18 '12 at 12:01

score 2 · Answer 1 · answered Nov 18 '12 at 11:42

2

echo '<tr><td> Sr.No</td>';
echo '<td width="16%" bgcolor="' . $colorVariable .  '"> delete</td>';
echo '<td> File Name </td>';
echo '<td> Share It</td></tr>';

answered Nov 18 '12 at 11:42

Vyacheslav Voronchuk

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19
16

score 2 · Answer 2 · answered Nov 18 '12 at 11:42

2

The "'s are colliding. You need to escape the character, like below.

echo"<td  width=\"16%\" bgcolor=\"#CCCCCC\"> delete</td>";

answered Nov 18 '12 at 11:42

PearsonArtPhoto

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17
111
142

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Did it work? If it did, you should click the check box below the number of votes. – PearsonArtPhoto Nov 18 '12 at 18:17

score 0 · Answer 3 · edited May 23 '17 at 12:12

try

echo '<td  width="16%" bgcolor="#CCCCCC"> delete</td>';

PHP double quote and single quote

$some="Oh god";

echo "My answer is $some ";

//result is: My answer is Oh god

In the above, using double quotes, the variable $someis evaluated within the quotes and the result isn't what is expected: the variable is evaluated to Oh god. Variables, but not functions or constants, are evaluated even when enclosed in double quotes.

echo 'My answer is $some';

//result is: My answer is $some.

When single quotes are used, as above, the variable isn't evaluated and is printed on the screen literally as $some.

good read

Is there a performance benefit single quote vs double quote in php?

how to apply bgcolor in table using echo command

3 Answers3