Echo specific part of cURL output?

Question

So I've got this:

$pageurl = "http://www.example.com";
$group = $_POST['group'];
$ch = curl_init();

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $pageurl);
curl_setopt($ch, CURLOPT_POSTFIELDS, "group=$group");
$result = curl_exec ($ch);
curl_close($ch);

Which returns a web page. What I want to do is display only a certain part of that page, for example a single table. How would I go about that?

Use DOMDocument to parse the HTML and get the part you need. — Aleks G, Nov 18 '12 at 18:33
possible duplicate of [How to parse and process HTML with PHP?](http://stackoverflow.com/questions/3577641/how-to-parse-and-process-html-with-php) — mario, Nov 18 '12 at 18:33

Waqar Alamgir · Answer 1 · 2012-11-21T08:05:43.107

1

You can try this library PHP Simple HTML DOM Parser

edited Nov 21 '12 at 08:05

answered Nov 19 '12 at 10:12

Waqar Alamgir

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Miloš Đakonović · Answer 2 · 2012-11-19T11:03:03.247

Provided code seems incorrect - before

curl_setopt($ch, CURLOPT_POSTFIELDS, "group=$group");

you should specify

curl_setopt($ch, CURLOPT_POST, true);

to make sure your cURL HTTP POST request is going to be established correctly. (otherwise HTTP GET is default)

To extract parts of returned HTML document, best way is by using strip_tags() function http://php.net/manual/en/function.strip-tags.php, which will clear your code from any parts of HTML you do not want.

Echo specific part of cURL output?

2 Answers2