Using preg_replace with ASCII characters

Question

In my functions.php I added a function that replaces English with German quotation marks. I do this by simple str_replace calls, like this:

 $content = str_replace (' &#8220;', ' &#8222;', $content);

Now I want to do this with preg_replace instead so I can handle special cases differently. However, this:

 $haekchenunten = "&#8220;";
 $regex = /^ . $haekchenunten . /;
 $content = preg_replace ($regex, '&#8222;', $content);

Leads to a blank page (PHP Fatal, I'd presume).

How can I use “ with preg_replace?

possible duplicate of [How to get useful error messages in PHP?](http://stackoverflow.com/questions/845021/how-to-get-useful-error-messages-in-php) — mario, Nov 19 '12 at 12:05

score 0 · Accepted Answer · answered Nov 19 '12 at 12:17

0

If this is your code, try to use quotation ;-)

 $regex = "/^" . $haekchenunten . "/";

answered Nov 19 '12 at 12:17

Trendfischer

1 Answers1