Open a URL in Android's web browser from application

Question

How can I open a url in the android web browser from my application on clicking a button.

I tried this :

Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));

startActivity(myIntent);

but I am getting exception:

but I got an Exception :

 "No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com"

Answer 1

You are doing it fundamentally correct, you just need to include the full url.

String strURL="http://www.google.com";
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));
startActivity(myIntent);

Basically, the http is the protocol. It is the computer's way of trying to figure out how you want to open it. You might also be interested in https, if you want a secure connection over SSL.

Answer 2

Almost seems like this would be useful to read... from the page:

Uri uri = Uri.parse("http://androidbook.blogspot.com");
Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uri);
startActivity(launchBrowser);

There is a second way, involving the WebView, but that seems like it's not your question. Hope this helped.

Answer 3

String url = "http://www.example.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);

Answer 4

Try this:

String strURL = "http://www.google.com";
        Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(strURL));

        startActivity(myIntent);

As for the missing "http://" I'd just do something like this:

if (!url.startsWith("http://") && !url.startsWith("https://"))
   url = "http://" + url;