Executing RESTful URL with Android

Question

I am trying to exectue the following REST url using Android but I get the following error,

11-23 12:12:32.749: E/AndroidRuntime(709): Caused by: java.lang.IllegalArgumentException: Illegal character in query at index 121: http://xxxxxxxxxxxxxxxxx.com/add.php?key=xxxxxxxxxxxx&type=Timbuktu&description=Africa&latitude=16.776767&longitude=-3.006361&private={"tag":"test"}

When I call the same URL in a browser, it works. Any help would be apprciated !

URLEncoder.encode(url, "UTF-8"); – Nirav Ranpara Nov 23 '12 at 12:24 — Nirav Ranpara, Nov 23 '12 at 12:24

score 4 · Accepted Answer · answered Nov 23 '12 at 12:23

4

Encode your url first, paramerters part only..

 URLEncoder.encode("key=xxxx&type=Timbuktu&description=Africa&latitude=16.776767&longitude=-3.006361&private={\"tag\":\"test\"}", "UTF-8")

answered Nov 23 '12 at 12:23

Nermeen

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Hey, I'm just trying this now but keep getting, {"status":"error","message":"Missing type parameter in http request"} back from the server. – TomSelleck Nov 23 '12 at 13:13

score 2 · Answer 2 · answered Nov 23 '12 at 12:23

You need to URL-encode the parameters of your URL, like this:

String privateParamValue = URLEncoder.encode("{\"tag\":\"test\"}", "UTF-8");
String url = "http://xxxx.com/add.php?key=xxxx&type=Timbuktu&description=Africa&latitude=16.776767&longitude=-3.006361&private=" + privateParamValue;

score 1 · Answer 3 · answered Nov 23 '12 at 12:23

1

Browsers are intelligent and encode the URL in UTF-8. I Think u should also do that at client end.

URLEncoder.encode(url, "UTF-8");

answered Nov 23 '12 at 12:23

Talha Ahmed Khan

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Executing RESTful URL with Android

3 Answers3