PHP - syntax error, unexpected T_CONSTANT_ENCAPSED_STRING

Question

I am very new to PHP and have no idea why this is happening, I have looked at other online items, however I just cannot seem to see why I am getting this error.

<?php
include_once('assets/libs/posicloud/posicloud.php');

    $cloud=new posicloud();
    $out='';
    foreach ($cloud->list_templates() as $key=>$template)
    {
$out.='<option value=''.$key.'">'.$value["name"].';
    }
  return $out;
?>

Thankyou for any help!

Thanks, apologies but I am very new, I have read the error messages but did not understand them, thats why I posted here to see if someone could help me understand my issue. — RossDoughty, Nov 26 '12 at 13:30
There's something wrong with your quotes notation. As this is a very important aspect of PHP (or programming in general), I recommend reading some more about it first before we give you a bite-sized answer. For example: http://www.trans4mind.com/personal_development/phpTutorial/quotes.htm — Joram van den Boezem, Nov 26 '12 at 13:44
I was receiving this error and had to convert the file line separators from CF to CRLF. — Enkode, Aug 30 '15 at 05:43

score 21 · Accepted Answer · answered Nov 26 '12 at 13:31

21

When you're working with strings in PHP you'll need to pay special attention to the formation, using " or '

$string = 'Hello, world!';
$string = "Hello, world!";

Both of these are valid, the following is not:

$string = "Hello, world';

You must also note that ' inside of a literal started with " will not end the string, and vice versa. So when you have a string which contains ', it is generally best practice to use double quotation marks.

$string = "It's ok here";

Escaping the string is also an option

$string = 'It\'s ok here too';

More information on this can be found within the documentation

answered Nov 26 '12 at 13:31

Rawkode

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Please remember to upvote/accept an answer if it worked for you. It'll guarantee future help down the line :-) – Rawkode Nov 26 '12 at 14:22
Ticked for most descriptive and helpful answer. – RossDoughty Nov 26 '12 at 14:59

score 2 · Answer 2 · answered Nov 26 '12 at 13:26

2

Wrong quoting: (and missing option closing tag xd)

$out.='<option value="'.$key.'">'.$value["name"].'</option>';

answered Nov 26 '12 at 13:26

aleation

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score 1 · Answer 3 · answered Nov 26 '12 at 13:25

1

'<option value=''.$key.'">'

should be

'<option value="'.$key.'">'

answered Nov 26 '12 at 13:25

Luca Rainone

16,138
2
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1

…or `sprintf( ' – feeela Nov 26 '12 at 13:26

score 1 · Answer 4 · answered Nov 26 '12 at 13:27

1

You have a sintax error in your code:

try changing this line

$out.='<option value=''.$key.'">'.$value["name"].';

with

$out.='<option value="'.$key.'">'.$value["name"].'</option>';

answered Nov 26 '12 at 13:27

Alessandro Cabutto

164
8

score 0 · Answer 5 · edited Apr 13 '18 at 07:18

0

$out.='<option value="'.$key.'">'.$value["name"];

me funciono con esta

"<a  href='javascript:void(0)' onclick='cargar_datos_cliente(\"$row->DSC_EST\")' class='button micro asignar margin-none'>Editar</a>";

edited Apr 13 '18 at 07:18

Eduardo Rosales Carlos

3
2

answered Nov 26 '12 at 13:26

silly

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PHP - syntax error, unexpected T_CONSTANT_ENCAPSED_STRING

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