Well, I've a weird problem with printf(). It's outputting garbage on the screen. It's kind of connected with memory, I guess. Have a look:
char string1[] = "SAMPLE STRING";
char string2[20]; // Some garbage in it
/* Let's clear this madness*/
int i = 0;
for (i; i < 20; i++) string2[i] = ' '; // Space, why not?
printf("output: %s", string2);
output: ╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠╠SAMPLE STRING
// Ten spaces and random characters, why?
Because C strings need to be NUL terminated. This means the last char of your string must be '\0'. This is how printf (and all other C string functions) know when a string is finished.
Finish your string2 with a null character, '\0':
string2[19] = '\0';
Or you can do it in this way:
for (i; i < 19; i++)
string2[i] = ' ';
string2[i] = '\0'; // After the end of the loop, i=19 here
#include <stdio.h>
int main() {
char string1[] = "SAMPLE STRING";
// Using curly braces {} for initialization
char string2[20] = {}; // Initialize all elements to 0 (null)
printf("Using curly braces initialization:\n");
printf("output: %s\n\n", string2);
// Using designated initializer for spaces and null-terminator
char string3[20] = {[0 ... 18] = ' '}; // Initialize elements 0 to 18 with spaces
printf("Using designated initializer for spaces:\n");
printf("output: %s\n\n", string3);
return 0;
}
