Undefined index in PHP errors

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PHP: “Notice: Undefined variable” and “Notice: Undefined index”
Undefined index in PHP

Notice: Undefined index: NAME in C:\xampp\htdocs\pmsx\lib\config.php on line 107

That's the exact error. Here's my code on the file. Thanks for those will help.

here's my line 107:

//echo "<br>" . $cdata;
// create the proper tree node if NAME attribute is set
if ($this->attr["NAME"] != "")
    $this->tags[count($this->tags) - 1] = $this->attr["NAME"];

Pastie link

exactly what does this have to with sql at all? sounds more like a DOM operation. did you check if the node you're on HAS a `NAME` attribute? — Marc B, Nov 26 '12 at 20:20
fwiw, your second line can be simplified `$this->tags[] = $this->attr["name"];` — Scott Evernden, Nov 26 '12 at 20:25
@ScottEvernden, for what I can tell, the original line overwrites the last element, whereas yours adds. Though, it looks like the original line just has an error. — Michael Krelin - hacker, Nov 26 '12 at 20:26

score 0 · Answer 1 · answered Nov 26 '12 at 20:22

0

NAME isn't a defined index. You probably want:

if( isset($this->attr['NAME']) && $this->attr['NAME'] != "" ) {
    // ...

answered Nov 26 '12 at 20:22

Cfreak

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Funny. The post is edited by `ComFreek`. Are you related? ;-) – Michael Krelin - hacker Nov 26 '12 at 20:25

score 0 · Answer 2 · answered Nov 26 '12 at 20:22

0

What you probably want is !empty($this->attr['NAME']) instead of $this->attr["NAME"]!="". Otherwise it errors out when NAME index is… well… undefined.

answered Nov 26 '12 at 20:22

Michael Krelin - hacker

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score 0 · Accepted Answer · answered Nov 26 '12 at 20:23

Use isset() first, to check, whether the property exists at all.

if ( isset( $this->attr["NAME"] ) && ($this->attr["NAME"] != "") ) {
    $this->tags[count($this->tags) - 1] = $this->attr["NAME"];
}

You error says, that the property NAME does not exist at all in the array attr!

Undefined index in PHP errors

3 Answers3