Trigraph characters

Question

c99 standard  5.2.1.1 Trigraph sequences

2 EXAMPLE The following source line

printf("Eh???/n");

becomes (after replacement of the trigraph sequence ??/)

printf("Eh?\n");

It's saying that it will replace the trigraph sequence, but it's not .

It's printing "Eh???/n"

Am I missing something ?

What compiler is this? Did you enable trigraphs? I believe they're disabled by default in a lot of compilers nowadays. — Mysticial, Nov 28 '12 at 07:38

score 5 · Accepted Answer · answered Nov 28 '12 at 07:42

5

Trigraphs are disabled by default in gcc. If you are using gcc then compile with -trigraphs to enable trigraphs:

gcc -trigraphs source.c

answered Nov 28 '12 at 07:42

P.P

score 1 · Answer 2 · answered Nov 07 '19 at 03:31

The ??/ in the printf is a trigraph character which is a part of C's preprocessor.

If you enable trigraph by using gcc -trigraphs source.c, it will convert ??/ into \. Your code will look like this:

printf("Eh???/n"); // Before enable trigraph

printf("Eh?\n"); // After enable trigraph

2 Answers2