I would like to know if there is an easy way to modify the Sankey diagram example so that there is smooth transition to new data. For example, imagine I have different datafiles (energy1.json, energy2.json ...) how could d3 plot a Sankey diagram for the first dataset, then waits and later on rearanges the boxes disposition to represent the second dataset?
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1Would all of your datafiles have the same nodes but different flows between them? – ASGM Mar 11 '13 at 23:38
2 Answers
This is possible. Here's one approach using a csv file. Working sankey here: https://www.betterment.com/resources/investment-strategy/portfolio-management/portfolio-diversification/
Define a global array outside of your d3.csv call.
var portfolioValues = [];
When parsing the csv to create the node/link structure, push values to your global array.
d3.csv("etf-geo.csv", function(error, data) { graph = {"nodes" : [], "links" : []}; data.forEach(function (d, i) { var item = { source: d.source, target: d.target, values: [] }; for (var j=0; j < 101; j++) { item.values.push(d['value'+j.toString()]); } portfolioValues.push(item); graph.nodes.push({ "name": d.source }); graph.nodes.push({ "name": d.target }); graph.links.push({ source: portfolioValues[i].source, target: portfolioValues[i].target, value: portfolioValues[i].values[startingAllocation] }); }); //this handy little function returns only the distinct / unique nodes graph.nodes = d3.keys( d3.nest() .key(function (d) { return d.name; }) .map(graph.nodes) ); // it appears d3 with force layout wants a numeric source and target // so loop through each link replacing the text with its index from node graph.links.forEach(function (d, i) { graph.links[i].source = graph.nodes.indexOf(graph.links[i].source); graph.links[i].target = graph.nodes.indexOf(graph.links[i].target); portfolioValues[i].source = graph.links[i].source; portfolioValues[i].target = graph.links[i].target; }); // now loop through each nodes to make nodes an array of objects // rather than an array of strings graph.nodes.forEach(function (d, i) { graph.nodes[i] = { "name": d }; }); // construct sankey sankey .nodes(graph.nodes) .links(graph.links) .layout();
Listen for a change and pass user input to your update function.
$(".sankey-slider").bind("slider:changed", function (event, data) { slideValue = data.value; updateData(parseInt(slideValue)); });
Create a temporary array and retrieve the correct values from the global array. Call the sankey functions to recalculate the layout.
var newLinks = []; portfolioValues.forEach(function(p, i) { newLinks.push({ source: p.source, target: p.target, value: p.values[allocation] }); }); graph.links = newLinks; sankey .nodes(graph.nodes) .links(graph.links) .size([width, height]) .layout();
Select each element that needs to be changed and pass the new data values.
d3.selectAll(".link") .data(graph.links) .attr("d", path) .attr("id", function(d,i){ d.id = i; return "link-"+i; }) .style("stroke-width", function(d) { return Math.max(1, d.dy); }) .sort(function(a, b) { return b.dy - a.dy; }); d3.selectAll(".node").attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; }); d3.selectAll("rect") .attr("height", function(d) { return d.dy; }) .on("mouseover",highlight_node_links) .on("mouseout",onNodeMouseout);
Working sankey here: https://www.betterment.com/resources/investment-strategy/portfolio-management/portfolio-diversification/

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Hi @Joe-Jansen is there a jsfiddle with your code. It will extremely useful to have an enviroment to fork and tweak as needed. – lwall Nov 25 '16 at 16:37
Since the automatic positioning of nodes includes a part which tries to minimize link distance in a connected graph which is an np optimization problem, any kind of optimizer can potentially jump from one minimum to another leading to a jump in layout. So a guaranteed smooth transition wont be possible.
The closest possible solution would probably be to linearly interpolate between the two input data sets and thereby generate a series of graphs which (depending on the data) more or less smoothly transition from one two the other.
Hope this helps.

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