Django - How to get and parse requested URL

Question

I have a blog application. and i want to set all user's accounts under subdomains. Like:

if someone type :

userx.blog.com

it must redirects to userx's blog page. i need to get that url and parse it from [].blog.com

and render requested user's page.

current profile url:

url(r'^blog/(?P<username>[-\w]+)/$', view='user_index',
name='user_index'),

in browser:

blog.com/blog/username

i hope i explained it clearly.

Thank you.

score 2 · Answer 1 · edited May 23 '17 at 12:18

2

I did something similar with one of my sites. My solution was to use mod_rewrite in apache to redirect userx.blog.com to blog.com/blog/userx.

http://httpd.apache.org/docs/2.2/rewrite/

Apache rewrite based on subdomain

Hope that helps.

edited May 23 '17 at 12:18

Community

1
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answered Nov 28 '12 at 14:03

themanatuf

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score 1 · Accepted Answer · answered Nov 28 '12 at 15:10

1

You can also make something what is called "internal redirect". This will allow you to hide from user that userx.blog.com is served actually by blog.com/blog/userx.

I also recommend to use nginx server as it is superior in every way over Apache :-)

answered Nov 28 '12 at 15:10

thedk

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i just passed to nginx. i want to keep url as userx.blog.com after page rendered. no redirection. is it internal redirect or rewrite rule? which one is correct way for my situation? – alioguzhan Dec 14 '12 at 12:30

Django - How to get and parse requested URL

2 Answers2