Display image in PHP given image content

Question

I'm using the GrabzIt PHP library and it returns screenshots of webpages.

The library returns the image content to be saved as a file, e.g:

file_put_contents('images/screenshot.png', $grabzitImageContents);

I want to display this image in the page without saving the image (uses server space). Is it possible?

score 1 · Answer 1 · answered Nov 28 '12 at 21:16

1

You could use a data URI:

$encoded = base64_encode($grabzitImageContents);
echo '<img src="data:image/png;base64,' . $encoded . '" />';

answered Nov 28 '12 at 21:16

cmbuckley

score 1 · Accepted Answer · answered Nov 28 '12 at 21:17

1

You could just send the header and then echo the data:

header("Content-Type: image/png");
echo $grabzitImageContents;

Try it.

answered Nov 28 '12 at 21:17

GregPK

This won't work if the OP's intention is to display it directly within an HTML page. – cmbuckley Nov 28 '12 at 21:18
Haha that's the first thing I tried. I think there's something wrong with the GrabzIt code because neither answer is working. Lemme check... – apparatix Nov 28 '12 at 21:19
@apparatix This should work, but your script should only echo out this and nothing else. The source of the image in the html would be the image generating script. – jeroen Nov 28 '12 at 21:20

2 Answers2