XML parsing /JAVA

Question

I have an XML, for example

<root>
 <config x="xxx" y="yyyy" z="zzz" />
 <properties>blah blah blah </properties>   
 <example>
   <name>...</name>
   <decr>...</descr>
 </example> 
 <example>
   <name>...</name>
   <decr>...</descr>
 </example> 
</root>

and I need to get nodes config, and properties and all values in it. Thank you

Step 1) try it yourself, step 2) if you have issues then come back and ask a specific question... — ramsinb, Nov 29 '12 at 07:26
Also use the exact xml file because it has few errors in your xml file . — thar45, Nov 29 '12 at 07:31

score 2 · Answer 1 · edited May 23 '17 at 12:18

2

Xpath can fetch you the data in the config tag. You need to create an expression first like this expression="//root/config/@x", to get value of x,y,z. For properties, follow this thread : Parsing XML with XPath in Java

Hope this helps

edited May 23 '17 at 12:18

Community

1
1

answered Nov 29 '12 at 07:30

SmartCoder

21
2

score 1 · Answer 2 · answered Nov 29 '12 at 07:27

1

DOM,DOM4J,SAX..

if the size of XML file is small,you can use DOM or DOM4J,but the size is big , you use the SAX

answered Nov 29 '12 at 07:27

SongGuang

71
2

score 1 · Answer 3 · answered Nov 29 '12 at 07:42

1

If you directly want to query or fetch data XPath can help, but if you want the data as Java Objects so that you can use it further then use JAXB

answered Nov 29 '12 at 07:42

Narendra Pathai

41,187
18
82
120

score 0 · Answer 4 · answered Nov 29 '12 at 08:23

You can use SAX parser to read the xml manipulate its event based parsing and consumes more memory. If your xml is big and requires lot of manipulations then go-for DOM/DOM4j either is good. DOM4L is very latest. DOM is widely used in industry.

Based on your requirement go for good parser.

Thanks, Pavan

XML parsing /JAVA

4 Answers4