DateTime format Regular expression YYYY/MM/DD hh:mm:ss

Question

Can someone write a regular expression to test this date format 2012/11/14 14:28:12?

I already have a regular expression for the date part:

/^\d{4}\/\d{2}\/\d{2}$/

How can I add to this to test for the presence of a time?

Are you sure that `9999/99/99 99:99:99` is the correct date? — Grzegorz Gierlik, Dec 03 '12 at 11:14
See here http://stackoverflow.com/questions/3143070/javascript-regex-iso-datetime — Anujith, Dec 03 '12 at 11:16

David Hellsing · Answer 1 · 2012-12-03T11:28:37.260

5

I‘d use the Date constructor instead to test a date in that format:

var isValid = !!new Date('2012/11/14 14:28:12').getTime();

Demo: http://jsfiddle.net/rwCeA/

Works in all my test browsers (safari/chrome/firefox/ie7+). The Date constructor takes many date variants, but you can combine this with a regexp to force a certain format.

edited Dec 03 '12 at 11:28

answered Dec 03 '12 at 11:21

David Hellsing

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score 4 · Answer 2 · answered Dec 03 '12 at 11:18

This fiddle http://jsfiddle.net/jstoolsmith/Db3JM/ I wrote recently is a more sophisticated piece of code, the relevant regular expression is :

/(?:(\d{4})([\-\/.])([0-3]?\d)\2([0-3]?\d)|([0-3]?\d)([\-\/.])([0-3]?\d)\6(\d{4}))(?:\s+([012]?\d)([:hap])([0-5]\d))?/i

DateTime format Regular expression YYYY/MM/DD hh:mm:ss

2 Answers2