Parsing and modifying xml string with sax parser

Question

I have an XML file, I need to search for a specific tag in it and update it's value. The problem is that, using Sax parser is "must". I have to find these tags by using Sax Parser "only", dom stax j4dom dom4j parsers are out of consideration.

Can I accomplish this task by converting my xml file to a string and parse it by using sax parser and append the new value by StringBuilder object? Would it be okay? Or what would you recommend?

check the link [http://stackoverflow.com/questions/4898590/generating-xml-using-sax-and-java](http://stackoverflow.com/questions/4898590/generating-xml-using-sax-and-java) — Jiji, Dec 03 '12 at 16:51
SAX is not meant for modifying an existing XML. Why dom etc. are out of consideration? — Aravind Yarram, Dec 03 '12 at 17:11

Evgeniy Dorofeev · Accepted Answer · 2012-12-03T17:54:23.610

This is a working code, just add missing imports. It uses SAX and changes <name>user1</name> to <name>user2</name>. If you figure out how it works plus read SAX API you can do anything with your xml. Note that SAX had been considered the most efficient xml parser until StAX came into being

public static void main(String[] args) throws Exception {
    String xml = "<users><user><name>user1</name></user></users>";
    XMLReader xr = new XMLFilterImpl(XMLReaderFactory.createXMLReader()) {
        private String tagName = "";
        @Override
        public void startElement(String uri, String localName, String qName, Attributes atts)
                throws SAXException {
            tagName = qName;
            super.startElement(uri, localName, qName, atts);
        }
        public void endElement(String uri, String localName, String qName) throws SAXException {
            tagName = "";
            super.endElement(uri, localName, qName);
        }
        @Override
        public void characters(char[] ch, int start, int length) throws SAXException {
            if (tagName.equals("name")) {
                ch = "user2".toCharArray();
                start = 0;
                length = ch.length; 
            }
            super.characters(ch, start, length);
        }
    };
    Source src = new SAXSource(xr, new InputSource(new StringReader(xml)));
    Result res = new StreamResult(System.out);
    TransformerFactory.newInstance().newTransformer().transform(src, res);
}

this is very useful just be careful about loading proper sax driver while using on different platforms — duckduckgo, Sep 01 '13 at 05:21

score 0 · Answer 2 · answered Dec 03 '12 at 17:04

0

SAX parser is not a bad choice if time is not a consideration and memory is.

answered Dec 03 '12 at 17:04

CodeDreamer

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Parsing and modifying xml string with sax parser

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