Why i get a empty array after position moved?

Question

I try to use code from this Move an array element from one array position to another to move arrays position

But why when i will move last to first so I get a empty array

i do like this...

my_array.move(my_array_length,0);

Demo : http://jsfiddle.net/Jsu7R/

score 4 · Accepted Answer · answered Dec 06 '12 at 13:25

4

Since javascript arrays are indexed from 0 upwards, your code:

my_array.move(my_array_length,0);

will need to change to :

my_array.move(my_array_length-1,0);

The length of your array has 5 elements, but the last element has an index of 4.

answered Dec 06 '12 at 13:25

Lee Taylor

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You might also consider changing the function to either pferform a no-op or throw an error if the old index is outside the bounds of the array – roryf Dec 06 '12 at 13:28

score 2 · Answer 2 · answered Dec 06 '12 at 13:24

The method "move" from the reference page gets old_index, new_index parameters. You supply the array's length as the first parameter, but your array has no element at this position.

If you call "move" with these parameters:

my_array.move(my_array_length - 1,0)

it will work as expected

Why i get a empty array after position moved?

2 Answers2