Error when get src from first image using php?

Question

I have a sample code:

$content = 'I have a image <img border="0" alt="581.jpg - 58.03 KB" src="581.jpg">';

And php

preg_match('/<img.+src=[\'"](?P<src>.+)[\'"].*>/i', $content, $image);
echo $image[0];

Result is: 581.jpg" border="0" alt="581.jpg - , How to fix it ?

Hello is my answer solving your question ? and helpful for you ? — NullPoiиteя, May 30 '13 at 09:40

score 1 · Answer 1 · edited May 23 '17 at 12:05

Writing a regex for this is ... problematic to say the least. I would recommend using this:

$dom = new DOMDocument;
$dom->loadHTML($content);
foreach ($dom->getElementsByTagName('img') as $node) {
    echo $node->getAttribute('src') . PHP_EOL;
}

Explanation:

The reasons why you shouldn't use regex for what you want is that the markup for HTML varies. The position of the src attribute can differ, it may use single quotes instead of double quotes(some HTML attributes don't need quotes, for example this syntax is correct: <img class=logo />), it may be uppercase, and probably other issues I can't think of right now.

Extra info:

Grabbing the href attribute of an A element

Error when get src from first image using php?

1 Answers1