Accessing PHP valiables fields names without using intermediate variables

Question

Possible Duplicate:
Get PHP class property by string

Is there a cleaner way to do this? it does not compile

$object1->name = 'my_name';
$object1->address = 'address';
$object2->somefield->($object1->name) = $object1;

it works only if i assign to another variable $object1->name

$object1->name = 'my_name';
$object1->address = 'address';
$temp = $object1->name;
$object2->somefield->$temp = $object1;

score 9 · Accepted Answer · answered Dec 11 '12 at 15:41

9

Try this:

$object2->somefield->{$object1->name} = $object1;

answered Dec 11 '12 at 15:41

aykut

+1, even this answer got too much up-votes :P – Shiplu Mokaddim Dec 11 '12 at 15:43
Good! Thank you!! It there some documentation to this somewhere? :) – Pulz Dec 11 '12 at 15:50
http://php.net/manual/en/language.types.string.php (under the 'Complex (curly) syntax' title) – aykut Dec 11 '12 at 15:53

1 Answers1