Arrays with string keys or nested quotes into a lambda function in php

Question

I want to create a lambda function, i'm doing this:

create_function('$range',  'return " ( ABS(a.price) > format_money($range["min"] AND ABS(a.price) <  format_money($range["max"]) ) OR a.price is null " ');

But the $range["min"] part breaks my attempt ... there's a problem with nested quotes and i don't know how to solve it , i don't even know if it is possible to do this or php is not that powerful, any light?

May be this helpful to you: http://stackoverflow.com/questions/1909002/what-use-is-lambda-in-php — GBD, Dec 12 '12 at 11:15

score 2 · Answer 1 · answered Dec 12 '12 at 11:18

2

Using escaped single quotes and a ; got it to parse, don't know about the execution.

create_function('$range',  'return \' ( ABS(a.price) > format_money($range["min"] AND ABS(a.price) <  format_money($range["max"]) ) OR a.price is null \'; ');

answered Dec 12 '12 at 11:18

jaudette

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score 1 · Answer 2 · answered Dec 12 '12 at 11:12

1

You cannot call variables inside of single quotes.

create_function('$range',  'return " ( ABS(a.price) > format_money('.$range["min"].' AND ABS(a.price) <  format_money('.$range["max"].') ) OR a.price is null " ');

answered Dec 12 '12 at 11:12

Adam Lavin

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but what i need is to pass $range["min"] as a string , not the value! – R01010010 Dec 12 '12 at 11:17

Benjamin Paap · Answer 3 · 2012-12-12T11:22:35.683

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I was able to get this done by concatenating your values to the string like this:

create_function('$range',  'return " ( ABS(a.price) > format_money(" . $range["min"] . " AND ABS(a.price) <  format_money(" . $range["max"] . ") ) OR a.price is null "; ');

The output of that function was:

string(92) " ( ABS(a.price) > format_money(10 AND ABS(a.price) <  format_money(20) ) OR a.price is null "

edited Dec 12 '12 at 11:22

answered Dec 12 '12 at 11:17

Benjamin Paap

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score 0 · Answer 4 · answered Dec 12 '12 at 11:15

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Forget it, it was wrongly composed, the correct way is:

create_function('$range',  'return " ( ABS(a.price) > ".format_money($range[\'min\'])." AND ABS(a.price) < ".format_money($range[\'max\'])." ) OR a.price is null "; ');

now it works!

answered Dec 12 '12 at 11:15

R01010010

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Arrays with string keys or nested quotes into a lambda function in php

4 Answers4