No superclass method when calling super in define_method

Question

Why do I get the following error talk: super: no superclass method talk (NoMethodError) when I override a method that already exists?
How could I fix this code to call the super method?

Here is the sample code I'm using

class Foo
  def talk(who, what, where)
    p "#{who} is #{what} at #{where}" 
  end
end

Foo.new.talk("monster", "jumping", "home")

class Foo
  define_method(:talk) do |*params|
    super(*params)
  end
end

Foo.new.talk("monster", "jumping", "home")

See http://stackoverflow.com/questions/4470108/when-monkey-patching-a-method-can-you-call-the-overridden-method-from-the-new-i/4471202#4471202 — Eric Walker, Dec 12 '12 at 19:04

MC2DX · Accepted Answer · 2012-12-12T19:11:48.837

5

It's not working because you overwrite #talk. Try this

class Foo
  def talk(who, what, where)
    p "#{who} is #{what} at #{where}" 
  end
end

Foo.new.talk("monster", "jumping", "home")

class Bar < Foo
  define_method(:talk) do |*params|
    super(*params)
  end
end

Bar.new.talk("monster", "table", "home")

edited Dec 12 '12 at 19:11

answered Dec 12 '12 at 18:48

MC2DX

562
1
7
19

2

He's ovewriting `#foo` rather than overriding `#foo`. – Eric Walker Dec 12 '12 at 19:03
I mean `#talk`, not `#foo`. – Eric Walker Dec 12 '12 at 19:10
Thanks. My brain wasn't working correctly. I thought it was something to do with the way I was using `define_method`. – austen Dec 12 '12 at 20:12

No superclass method when calling super in define_method

1 Answers1