converting byte array of decimal value to hexadecimal string in java

Question

i m new to java. i want to convert a byte array of decimal value to hexadecimal string. my input byte array is [0, 0, 0, 0, 0, 0, 1, -28]. i m getting 00000000000001e4 instead of 0000001e4. plz help me to solve this problem

 public static String ConvetToHex(byte[] decValue) 
{

    String value = "";
    for(int i = 0;i<decValue.length;i++)
    {
         value = value+ Integer.toString((decValue[i] & 0xff) + 0x100, 16).substring(1);
    }
    return value;
}

score 2 · Answer 1 · answered Dec 13 '12 at 11:39

2

It looks correct to me. Eight bytes should turn into 16 hex characters. You can use

return new BigInteger(1, decValue).toString(16);

but it will produce the same output.

answered Dec 13 '12 at 11:39

Peter Lawrey

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but is there anyway to get in the specified format..? – Sachin K S Dec 13 '12 at 11:41
1

Sure you can but you will produce a number which is meaningless as there is no way to read the value correctly. – Peter Lawrey Dec 13 '12 at 11:44
For example in the format you suggest there is no way to tell if `1001` is `10`, `01` (as it should be) or `10`, `0`, `1` or `1`,`0`,`0`,`1`. – Peter Lawrey Dec 13 '12 at 11:48
i wrote the same code in .NET like value = value + Convert.ToInt32(decvalue[i]).toString("x"); i got the output which i mentioned. – Sachin K S Dec 13 '12 at 11:53
You can write the code in Java too. Doesn't change the fact that the format is broken. – Peter Lawrey Dec 13 '12 at 11:54
Try the output for [1,0,1,0] and [16,16] and you will find they are the same with this format so there is no way to know what it should be. – Peter Lawrey Dec 13 '12 at 11:57

converting byte array of decimal value to hexadecimal string in java

1 Answers1