HTTP Status 500 - null

Question

I wrote a java servlet program but when i run it, It was showing the Error HTTP Status 500 - null What it means ; My source code is on this page.

The error was

HTTP Status 500 - null
type Exception report
message null
description The server encountered an internal error that prevented it from fulfilling this request.
exception
 java.lang.NumberFormatException: null
java.lang.Integer.parseInt(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
skypark.Registration.doPost(Registration.java:56)
javax.servlet.http.HttpServlet.service(HttpServlet.java:647)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)

Please help me to resolve this....

score 2 · Answer 1 · answered Dec 16 '12 at 20:15

2

possibly

int phone=Integer.parseInt(phone1);

phone1 is null passed

answered Dec 16 '12 at 20:15

jmj

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score 0 · Answer 2 · answered Dec 17 '12 at 06:11

0

hey correct ur html there is no input type =number just correct as follows

Phone Number
</td><td>
<input type="text" name="phone">
</td></tr><tr><td>

answered Dec 17 '12 at 06:11

Nipun Jain

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score 0 · Answer 3 · answered Dec 17 '12 at 06:38

0

From the error I can say that there is something other than a numberpassed to your function and this exception is raised.

Something like this:

int a = Integer.ParseInt(aStr);

where the aStr is abc

answered Dec 17 '12 at 06:38

Matin Kh

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score 0 · Answer 4 · edited Feb 19 '13 at 09:50

0

You should have attribute name in the input tag.

<input type="text" name="xyz">

In d servlet access the value after parsing it, as follows.

int x=Integer.parseInt(request.getParameter("xyz"));

edited Feb 19 '13 at 09:50

psubsee2003

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answered Feb 19 '13 at 09:31

Tweety

1
1

HTTP Status 500 - null

4 Answers4