I have a list of lists called sorted_lists
I'm using this to write them into a txt file. Now the thing is, this line below prints ALL the lists. I'm trying to figure it out how to print only first n (n = any number), for example first 10 lists.
f.write ("\n".join("\t".join (row) for row in sorted_lists)+"\n")
Try the following:
f.write ("\n".join("\t".join (row) for row in sorted_lists[0:N])+"\n")
where N is the number of the first N lists you want to print.
sorted_lists[0:N] will catch the first N lists (counting from 0 to N-1, there are N lists; list[N] is excluded). You could also write sorted_lists[:N] which implicitly means that it will start from the first item of the list (item 0). They are the same, the latter may be considered more elegant.
f.write ('\n'.join('\t'.join(row) for row in sorted_lists[:n+1])+'\n')
where n is the number of lists.
Why not simplify this code and use the right tools:
from itertools import islice
import csv
first10 = islice(sorted_lists, 10)
with open('output.tab', 'wb') as fout:
tabout = csv.writer(fout, delimiter='\t')
tabout.writerows(first10)
You should read up on the python slicing features.
If you want to look at only the first 10 entires of sorted_lists, you could do sorted_lists[0:10].
