Adding one day to a date

Question

My code to add one day to a date returns a date before day adding: 2009-09-30 20:24:00 date after adding one day SHOULD be rolled over to the next month: 1970-01-01 17:33:29

<?php

    //add day to date test for month roll over

    $stop_date = date('Y-m-d H:i:s', strtotime("2009-09-30 20:24:00"));

    echo 'date before day adding: '.$stop_date; 

    $stop_date = date('Y-m-d H:i:s', strtotime('+1 day', $stop_date));

    echo ' date after adding one day. SHOULD be rolled over to the next month: '.$stop_date;
?>

I have used pretty similar code before, what am I doing wrong here?

w35l3y · Accepted Answer · 2015-07-04T14:29:43.943

414

<?php
$stop_date = '2009-09-30 20:24:00';
echo 'date before day adding: ' . $stop_date; 
$stop_date = date('Y-m-d H:i:s', strtotime($stop_date . ' +1 day'));
echo 'date after adding 1 day: ' . $stop_date;
?>

For PHP 5.2.0+, you may also do as follows:

$stop_date = new DateTime('2009-09-30 20:24:00');
echo 'date before day adding: ' . $stop_date->format('Y-m-d H:i:s'); 
$stop_date->modify('+1 day');
echo 'date after adding 1 day: ' . $stop_date->format('Y-m-d H:i:s');

edited Jul 04 '15 at 14:29

answered Sep 08 '09 at 16:00

w35l3y

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Thanks. Solved it as: $stop_date = date('Y-m-d H:i:s', strtotime( "$stop_date + 1 day" )); – ian Sep 08 '09 at 16:07
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You should not use a variable in a string. You should use:`date('Y-m-d H:i:s', strtotime($stop_date . ' + 1 day'));` as in the answer that @w35l3y gave you. – Cas Bloem Feb 12 '14 at 09:52
You should add a call to date_default_timezone_set function before running this code. For example add date_default_timezone_set('Europe/Rome'); – Luca Mastrostefano Jul 09 '17 at 11:26
Error: Call to a member function modify() on a non-object in /public_html/untitled5.php on line 72 – hamish Jul 23 '21 at 03:28
You did something wrong, @hamish - https://www.php.net/manual/en/datetime.modify.php#example-2002 – w35l3y Jul 28 '21 at 20:23
PHP Fatal error: Uncaught Error: Call to undefined method DateTime::modifiy(). By the way, using "/usr/local/php74/bin/php" to execute php file. It just doesn't work. – Gabe Hiemstra Jul 21 '22 at 07:43
it is "modify", not "modifiy" @GabeHiemstra – w35l3y Jul 26 '22 at 21:35

Prasanth Bendra · Answer 2 · 2017-02-17T10:24:13.410

134

$date = new DateTime('2000-12-31');

$date->modify('+1 day');
echo $date->format('Y-m-d') . "\n";

edited Feb 17 '17 at 10:24

answered Mar 22 '13 at 06:33

Prasanth Bendra

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This is a more recent -perfect- solution. – Cas Bloem Feb 12 '14 at 09:56
...As long as it doesn't cause fatal errors when run on your host ;) – Henrik Erlandsson Jan 13 '15 at 13:18
Don't apologize. Some people posted the dame answer 3 years after you did – Mawg says reinstate Monica Feb 12 '16 at 16:34
1

You should add a call to date_default_timezone_set function before running this code. For example add date_default_timezone_set('Europe/Rome'); – Luca Mastrostefano Jul 09 '17 at 11:26
2

@LucaMastrostefano no, you should have the timezone set on your server... – M H Apr 26 '18 at 20:23
this should be an accepted answer because it works for both latest date and any other date while the accepted answer only works for latest date. kudos – Nasz Njoka Sr. Jul 24 '19 at 18:48
fatal error on my side. probably only for new php servers. – hamish Jul 23 '21 at 03:37

score 85 · Answer 3 · edited Jan 29 '18 at 11:17

85

It Worked for me: For Current Date

$date = date('Y-m-d', strtotime("+1 day"));

for anydate:

date('Y-m-d', strtotime("+1 day", strtotime($date)));

edited Jan 29 '18 at 11:17

Lucky Bastard

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answered Nov 20 '17 at 13:03

Jay Momaya

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thanks it worked for me. Simplest of all solution given. – Puneet Verma Dec 13 '17 at 13:42
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you don't need to repeat and nest `strtotime()` - it can handle everything in one call: `date('Y-m-d', strtotime($date . " +1 day"));` – But those new buttons though.. Nov 13 '18 at 16:58
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Nice, This is the simplest solution! Thank you – Angel Dec 10 '19 at 03:14

score 33 · Answer 4 · answered Mar 19 '15 at 10:22

33

Simplest solution:

$date = new DateTime('+1 day');
echo $date->format('Y-m-d H:i:s');

answered Mar 19 '15 at 10:22

minlare

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I like your way in a one liner `echo (new DateTime('+1 day'))->format('Y-m-d H:i:s');` – Aba Jul 01 '16 at 14:28
@Aba I don't think your one liner works in older versions of PHP because I tried it and I got an error: `Unexpected T_OBJECT_OPERATOR” error in PHP` – Zachary Weixelbaum Sep 01 '17 at 12:20

score 9 · Answer 5 · answered Feb 18 '15 at 12:28

9

Simple to read and understand way:

$original_date = "2009-09-29";

$time_original = strtotime($original_date);
$time_add      = $time_original + (3600*24); //add seconds of one day

$new_date      = date("Y-m-d", $time_add);

echo $new_date;

answered Feb 18 '15 at 12:28

joan16v

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This will sometimes fail on daylight savings changes when the day length is not 24 hours. – Nik Dow Feb 21 '16 at 21:34

score 7 · Answer 6 · edited Dec 30 '13 at 14:30

7

Try this

echo date('Y-m-d H:i:s',date(strtotime("+1 day", strtotime("2009-09-30 20:24:00"))));

edited Dec 30 '13 at 14:30

SeanWM

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answered Dec 27 '13 at 09:26

user1987095

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Thanks mate. It helped me. – Vandolph Reyes Oct 02 '17 at 14:50

score 7 · Answer 7 · edited Oct 07 '17 at 01:57

7

The modify() method that can be used to add increments to an existing DateTime value.

Create a new DateTime object with the current date and time:

$due_dt = new DateTime();

Once you have the DateTime object, you can manipulate its value by adding or subtracting time periods:

$due_dt->modify('+1 day');

You can read more on the PHP Manual.

edited Oct 07 '17 at 01:57

Toastrackenigma

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answered Oct 06 '17 at 23:05

Kal

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score 4 · Answer 8 · answered Sep 08 '09 at 15:58

4

I always just add 86400 (seconds in a day):

$stop_date = date('Y-m-d H:i:s', strtotime("2009-09-30 20:24:00") + 86400);

echo 'date after adding 1 day: '.$stop_date;

It's not the slickest way you could probably do it, but it works!

answered Sep 08 '09 at 15:58

Doug Hays

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How do you deal with leap seconds when adding 86400 won't work as there's 86401 seconds in that day? (ok, I know it only happens every few years, but depending on the app this might be important) – Glen Sep 08 '09 at 16:05
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Not all days have 86400 seconds in them. In fact, in most places in the US there are 3600 fewer or additional seconds twice a year. – Peter Kovacs Sep 08 '09 at 16:10
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You can safely ignore leap seconds, since "Unix time" does. This is somewhat complicated, but read this article for more info: http://derickrethans.nl/leap_seconds_and_what_to_do_with_them.php – Christian Davén Sep 08 '09 at 17:47
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You should avoid this solution. Here is why: http://stackoverflow.com/questions/2613338/date-returning-wrong-day-although-the-timestamp-is-correct – mspir Sep 21 '12 at 20:23
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Do not add date by adding 86400 seconds to previous day! You will have bug in your code! This does not work on Daylight Saving days! – sbrbot Oct 26 '12 at 09:05

score 1 · Answer 9 · answered Sep 08 '09 at 16:03

While I agree with Doug Hays' answer, I'll chime in here to say that the reason your code doesn't work is because strtotime() expects an INT as the 2nd argument, not a string (even one that represents a date)

If you turn on max error reporting you'll see this as a "A non well formed numeric value" error which is E_NOTICE level.

Smar ts · Answer 10 · 2020-10-24T01:07:01.443

1

<?php

function plusTimetoOldtime($Old_Time,$getFormat,$Plus_Time) {
    return date($getFormat,strtotime(date($getFormat,$Old_Time).$Plus_Time));
}

$Old_Time = strtotime("now");
$Plus_Time = '+1 day';
$getFormat = 'Y-m-d H:i:s';

echo plusTimetoOldtime($Old_Time,$getFormat,$Plus_Time);

?>

edited Oct 24 '20 at 01:07

answered Oct 14 '20 at 22:55

Smar ts

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score 0 · Answer 11 · answered Nov 06 '16 at 00:06

The following code get the first day of January of current year (but it can be a another date) and add 365 days to that day (but it can be N number of days) using DateTime class and its method modify() and format():

echo (new DateTime((new DateTime())->modify('first day of January this year')->format('Y-m-d')))->modify('+365 days')->format('Y-m-d');

NVRM · Answer 12 · 2022-08-26T17:09:32.473

0

As we often receive ISO strings via an API from another time zone, we can make the conversion to local time on the fly:

// The machine local time is GMT+2, but we received a date at GMT+0 (UTC)
echo date(DATE_ISO8601, strtotime("-1 hour", strtotime("2022-08-17T23:25:51-00:00")));
// 2022-08-18T00:25:51+0200

edited Aug 26 '22 at 17:09

answered Aug 17 '22 at 02:04

NVRM

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But those new buttons though.. · Answer 13 · 2022-08-23T02:21:18.883

-1

You can add one day to today's date using DateTime() and DateInterval() like this:

echo (new DateTime())->add(new DateInterval('P1D'))->format('Y-m-d');

OR a specific date:

$date = '2009-09-30 20:24:00';
echo (new DateTime($date))->add(new DateInterval('P1D'))->format('Y-m-d');

edited Aug 23 '22 at 02:21

answered Jul 11 '22 at 18:13

But those new buttons though..

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Adding one day to a date

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