What is the difference between Math.Floor()
and Math.Truncate()
in .NET?

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13e.g. Math.Floor(5.4) = 5 Math.Truncate(5.4) = 5 – subramani Dec 14 '11 at 10:49
13 Answers
Math.Floor
rounds down, Math.Ceiling
rounds up, and Math.Truncate
rounds towards zero. Thus, Math.Truncate
is like Math.Floor
for positive numbers, and like Math.Ceiling
for negative numbers. Here's the reference.
For completeness, Math.Round
rounds to the nearest integer. If the number is exactly midway between two integers, then it rounds towards the even one. Reference.
See also: Pax Diablo's answer. Highly recommended!

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34@Chris, I suggest you fix your description of Round, there's two ways to round (AwayFromZero and ToEven) and it doesn't round to the nearest *integer* since it can do fractional rounding as well. – paxdiablo Feb 24 '09 at 02:44
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2So just a short add on to the original question - what is the difference between Math.Truncate and just casting a decimal or double to int? wouldn't it also just round towards zero? – Noam Gal May 19 '09 at 10:40
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Follow these links for the MSDN descriptions of:
Math.Floor
, which rounds down towards negative infinity.Math.Ceiling
, which rounds up towards positive infinity.Math.Truncate
, which rounds up or down towards zero.Math.Round
, which rounds to the nearest integer or specified number of decimal places. You can specify the behavior if it's exactly equidistant between two possibilities, such as rounding so that the final digit is even ("Round(2.5,MidpointRounding.ToEven)
" becoming 2) or so that it's further away from zero ("Round(2.5,MidpointRounding.AwayFromZero)
" becoming 3).
The following diagram and table may help:
-3 -2 -1 0 1 2 3
+--|------+---------+----|----+--|------+----|----+-------|-+
a b c d e
a=-2.7 b=-0.5 c=0.3 d=1.5 e=2.8
====== ====== ===== ===== =====
Floor -3 -1 0 1 2
Ceiling -2 0 1 2 3
Truncate -2 0 0 1 2
Round (ToEven) -3 0 0 2 3
Round (AwayFromZero) -3 -1 0 2 3
Note that Round
is a lot more powerful than it seems, simply because it can round to a specific number of decimal places. All the others round to zero decimals always. For example:
n = 3.145;
a = System.Math.Round (n, 2, MidpointRounding.ToEven); // 3.14
b = System.Math.Round (n, 2, MidpointRounding.AwayFromZero); // 3.15
With the other functions, you have to use multiply/divide trickery to achieve the same effect:
c = System.Math.Truncate (n * 100) / 100; // 3.14
d = System.Math.Ceiling (n * 100) / 100; // 3.15

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8Pax, I think you've got a mistake with: Round(AwayFromZero) -3 -2 1 2 3 Math.Round(-1.2, MidpointRounding.AwayFromZero) == -1 Math.Round(0.3, MidpointRounding.AwayFromZero)==0.0 etc.. – dtroy May 05 '09 at 03:49
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1Thanks, @dtroy, I've never had a need to use that mode and, while I documented it correctly if the text, I totally got the examples wrong. Hopefully that's fixed now. – paxdiablo May 05 '09 at 04:16
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Sorry to comment on such an old question but I have to ask: How can you round "ToEven" to two decimal places? Surely odd and even apply only to integers? – Richiban Nov 20 '14 at 16:10
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6@Richiban, think of `even` as a property of the final *digit* in the rounded number, not as meaning the entire *number* must be a multiple of two. By the way, sorry it took so long to get back to you, hope you weren't just sitting around waiting for my response :-) – paxdiablo Aug 05 '15 at 05:10
Math.Floor()
rounds toward negative infinity
Math.Truncate
rounds up or down towards zero.
For example:
Math.Floor(-3.4) = -4
Math.Truncate(-3.4) = -3
while
Math.Floor(3.4) = 3
Math.Truncate(3.4) = 3

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Math.floor
sliiiide to the left...
Math.ceil
sliiiide to the right...
Math.truncate
criiiiss crooooss (floor/ceil always towards 0)
Math.round
cha cha, real smooth... (go to closest side)
Let's go to work! (⌐□_□)
To the left... Math.floor
Take it back now y'all... --
Two hops this time... -=2
Everybody clap your hands ✋✋
How low can you go? Can you go down low? All the way to the floor
?
if (this == "wrong")
return "i don't wanna be right";
Math.truncate(x)
is also the same as int(x)
.
by removing a positive or negative fraction, you're always heading towards 0.

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Some examples:
Round(1.5) = 2
Round(2.5) = 2
Round(1.5, MidpointRounding.AwayFromZero) = 2
Round(2.5, MidpointRounding.AwayFromZero) = 3
Round(1.55, 1) = 1.6
Round(1.65, 1) = 1.6
Round(1.55, 1, MidpointRounding.AwayFromZero) = 1.6
Round(1.65, 1, MidpointRounding.AwayFromZero) = 1.7
Truncate(2.10) = 2
Truncate(2.00) = 2
Truncate(1.90) = 1
Truncate(1.80) = 1

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They are functionally equivalent with positive numbers. The difference is in how they handle negative numbers.
For example:
Math.Floor(2.5) = 2
Math.Truncate(2.5) = 2
Math.Floor(-2.5) = -3
Math.Truncate(-2.5) = -2
MSDN links: - Math.Floor Method - Math.Truncate Method
P.S. Beware of Math.Round it may not be what you expect.
To get the "standard" rounding result use:
float myFloat = 4.5;
Console.WriteLine( Math.Round(myFloat) ); // writes 4
Console.WriteLine( Math.Round(myFloat, 0, MidpointRounding.AwayFromZero) ) //writes 5
Console.WriteLine( myFloat.ToString("F0") ); // writes 5
Try this, Examples:
Math.Floor() vs Math.Truncate()
Math.Floor(2.56) = 2
Math.Floor(3.22) = 3
Math.Floor(-2.56) = -3
Math.Floor(-3.26) = -4
Math.Truncate(2.56) = 2
Math.Truncate(2.00) = 2
Math.Truncate(1.20) = 1
Math.Truncate(-3.26) = -3
Math.Truncate(-3.96) = -3
Also Math.Round()
Math.Round(1.6) = 2
Math.Round(-8.56) = -9
Math.Round(8.16) = 8
Math.Round(8.50) = 8
Math.Round(8.51) = 9
math.floor()
Returns the largest integer less than or equal to the specified number. MSDN system.math.floor
math.truncate()
Calculates the integral part of a number. MSDN system.math.truncate

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Math.Floor()
rounds
"toward negative infinity" in compliance to IEEE Standard 754 section 4.
Math.Truncate()
rounds " to the nearest integer towards zero."
Math.Floor()
: Returns the largest integer less than or equal to the specified double-precision floating-point number.
Math.Round()
: Rounds a value to the nearest integer or to the specified number of fractional digits.
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1The OP asked about the difference between `Floor()` and `Truncate()`, not `Floor()` and `Round()`. – Robert Columbia Nov 11 '17 at 00:38
Math.floor()
will always round down ie., it returns LESSER integer. While round()
will return the NEAREST integer
math.floor()
Returns the largest integer less than or equal to the specified number.
math.truncate()
Calculates the integral part of a number.

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Math.Floor() :
It gives the largest integer less than or equal to the given number.
Math.Floor(3.45) =3
Math.Floor(-3.45) =-4
Math.Truncate():
It removes the decimal places of the number and replace with zero
Math.Truncate(3.45)=3
Math.Truncate(-3.45)=-3
Also from above examples we can see that floor and truncate are same for positive numbers.

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Going by the Mathematical Definition of Floor, that is, "Greatest integer less than or equal to a number", This is completely unambiguous, whereas, Truncate just removes the fractional part, which is equivalent to round towards 0.

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