atexit() function bionic vs glibc

Question

I found interesting moment: the atexit() function works differently for bionic and glibc. Here is an example:

#include <cstdlib>
#include <cstdio>
extern "C" {
    void one(){
    printf("one\n");
    }
    void two() {
    printf("two\n");
    atexit(one);
    }
}
int main() {
    atexit(two);
}

Results for bionic:

two

Results for glibc:

two
one

Why do the results differ?

score 3 · Accepted Answer · answered Dec 25 '12 at 11:40

3

It is unspecified whether a call to the atexit function that does not happen before the exit function is called will succeed.

ISO C standard, §7.22.4.2. So both behaviors are compliant; you can't reliably register a function using atexit while exit is already running its atexit handlers.

answered Dec 25 '12 at 11:40

Fred Foo

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Where i can found standart? do you mean 7.20.4.2> – Laser Dec 25 '12 at 11:44

score 1 · Answer 2 · answered Dec 25 '12 at 11:40

1

This behavior is unspecified. You can define multiple functions to be called using atexit() multiple times, but you must not use it once you're already exiting the program (i.e. once you've left main()).

answered Dec 25 '12 at 11:40

Mario

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atexit() function bionic vs glibc

2 Answers2